Here's the work for that problem.
-3x+ 8.1= -18.9
-3x=-18.9-8.1 (subtracting 8.1 from both sides, or, moving it to the other side)
-3x=-27
x=27
23
3x=81 3x/3=81/3x=27
If 3x = 81 then x = 27 and 27 cubed = 19683
(3X + 9) (X + 9)
no because it has an equal symbol in it
23
3x=81 3x/3=81/3x=27
If 3x = 81 then x = 27 and 27 cubed = 19683
6x+11=92-3x +3x +3x 9x+11=92 -11 -11 9x=81 divide by 9 x=9
The problem '3x+9=81-5' can be solved as follows - 3x+9=81-5x Original Problem 3x=72-5x Subtract 9 from both sides of the equation 8x=72 Add '5x' to both sides of the equation x=9 Divide both sides by 8
9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 = (3x - y - 9)*(3x - y + 9)
9x^2-6xy+y^2 = (y-3x)^2 (y-3x)^2-81 -> ((y-3x)+9)((y-3x)-9)
13
9x2 - 6xy + y2 - 81 = (3x - y)2 - 92 = (3x - y - 9)(3x - y + 9)
(3X + 9) (X + 9)
no because it has an equal symbol in it
9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 (since the first three terms make a perfect square = (3x - y - 9)(3x - y + 9) since the expression now is a difference of two squares.