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so you are talking about 2x^2 - 11x + 14 ... So then you found the Common factor from the two pairs. Then you would do 2x^2 - 4x - 7x + 14. 2(x^2-2x) - (7x-2). If you rewrite it in factor form, then it would be (2x−7)(x−2). If you try to find what x is, then you would have two different sets now. 2x - 7 and x - 2. Move the number to the other side... 2x = 7 and x = 2. (2x = 7) = (x = 7/2).

Simply the equation: (2x−7)(x−2)

Solving for x: x = 7/2 or 2

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(9x + 7)(x - 2)

If you mean 8+11x = -14 then the value of x works out as -2

(x - 2)(2x + 7)

(y - 2)(y - 7)

It is: (x-2)(x-7) when factored

2(x - 7)(x - 1)

Distance travelled = 5x3 - 6x2 + 3x + 14 = 5x3 + 5x2 - 11x2 - 11x + 14x + 14 = 5x2(x + 1) - 11x(x + 1) + 14(x + 1) = (x + 1)(5x2 - 11x + 14) Then time = distance/rate = (x + 1)(5x2 - 11x + 14) / (x+1) = 5x2 - 11x + 14

9x2+11x-14 = (9x-7)(x+2) when factored with the help of the quadratic equation formula.

14 + 2x + 9x - 6 - 11x 14 - 6 + 2x + 9x - 11x The x values cancel themselves out, leaving just the number value The answer is therefore 8.

It is: (g-5)(g-9)

You look for two integers which multiply to 33 and whose sum is 14 and these happen to be 11 and 3. So x^2 - 14x + 33 = x^2 - 3x - 11x + 33 =(x^2 - 3x) - (11x - 33) [sign for 33 changes because the bracket has a minus sign] =x * (x-3) + 11 * (x-3) =(x - 3) * (x - 11)

It can't be solved because the discriminant of this quadratic equation is less than zero

24 plus 14 minus 8 = 18

-11x + 13

That factors to (x - 14)(x + 14)

x2-5x-14 = (x+2)(x-7) when factored

With the help of the quadratic equation formula

(x - 14)(x + 14)

(2x - 7)(x - 2)

x = -2/3,7/6

14 squared = 196, so you're looking for the sqrt of double that, ie 392, which is almost exactly 19.8

4(h2 - 14)

3 + 6 - 2 + 14 - 3 + 2 = 20

4 - 7 + 14 + 2 - 19 + 6 = 0

If that's +11x + 14, the answer is (x + 2)(2x + 7)