a2 + -5a2 - a2 - a = a2 - 5a2 - a2 - a = a2 - 6a2 - a = -5a2 - a
5a or 4a squared
This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number. 25a(2) - 20ab + 4b(2) (2b-5a)(2b-5a) This is: 2bx2b=4b(2) 2bx-5a=-10ab (twice) -5ax-5a=25a
The square root of 25a squared is 5a. The square root of 16 is 4.So the answer is (5a+4)(5a-4)
2a + 5a + 3a = 10a
5a(2b + 1)
No
It simplifies to 5a+4 !
92
5a or 4a squared
(5a)2 = 25a2
This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number. 25a(2) - 20ab + 4b(2) (2b-5a)(2b-5a) This is: 2bx2b=4b(2) 2bx-5a=-10ab (twice) -5ax-5a=25a
2a + 3a = 5a
The square root of 25a squared is 5a. The square root of 16 is 4.So the answer is (5a+4)(5a-4)
(a2 + 5a + 6)/(a - 2) = (a + 2)*(a 3)/(a - 2) which cannot be simplified further. It can, however be written as (a2 - 2a + 7a - 14 + 20)/(a - 2) which is (a + 7) + 20/(a - 2)
5a + 3 + (2a - 2) + a= 5a + 3 + 2a - 2 + a= 8a + 1
5a
2a + 5a + 3a = 10a