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Q: What is the answer to log4 (3x 5)(x-6)3?

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log3 81 × log2 8 × log4 2 = log3 (33) × log2 (23) × log4 (40.5) = 3 × (log3 3) × 3 × (log2 2) × 0.5 × (log4 4) = 3 × 1 × 3 × 1 × 0.5 × 1 = 9 × 0.5 = 4.5

It is 2.1240

The rule for converting log bases is: log4(7) = log2(7)/log2(4) Now 4 = 2 squared so log2(4) = 2 So log4(7) = log4(7)/2 = (1/2)*log2(7) By the way, the "new and improved" browser now does not accept subscripts or superscripts so I hope you understand this.

630

3x 3x 3x is 27x3

log4+log3=log(4x3)=log12

3x + 3x + 3x = 3* (3x) = 9x

the value of log (log4(log4x)))=1 then x=

3x-3x equal = 0

3x^5 If these are 5 of 3x multiplied together the it must be (3x)^5 =3^5 times x^5

3x. 15x - 9x = 6x 9x - 6x = 3x 6x - 3x = 3x 3x - 3x = 0

9x2 + 6x + 1 = 9x2 + 3x + 3x + 1 = 3x(3x + 1) + 1(3x + 1) = (3x + 1)(3x + 1) or (3x +1)2

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