Best Answer

rad 12 - 3 rad 3

rad 12 = rad(4*3) = rad (4) * rad(3) = 2 rad 3

2 rad 3 - 3 rad 3

= - rad 3

Q: What is the answer to radical 12 minus 3 radical 3?

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Start by finding a common denominator. If the radical includes the entire fraction (3/4 for the first part), the common denominator would be square root of 12.

3 - (-12) = 3 + 12 = 15.

2√20 - 3√7 - 2√5 + 4√63 = 2√(4 x 5) - 3√7 - 2√5 + 4√(9 x 7) = 4√5 - 2√5 - 3√7 + 12√7 = 2√5 + 9√7

4 x2

If we read this carefully, what you're asking for is (4 of something) minus (1 of the same thing). The result is 3 of them . . . 3 radical 6.

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Start by finding a common denominator. If the radical includes the entire fraction (3/4 for the first part), the common denominator would be square root of 12.

A Huge ASS

15

3 - (-12) = 3 + 12 = 15.

2√20 - 3√7 - 2√5 + 4√63 = 2√(4 x 5) - 3√7 - 2√5 + 4√(9 x 7) = 4√5 - 2√5 - 3√7 + 12√7 = 2√5 + 9√7

4 x2

If we read this carefully, what you're asking for is (4 of something) minus (1 of the same thing). The result is 3 of them . . . 3 radical 6.

minus 21 think of it as 12+9 which equals 21 then just whack a minus sign infront

In order to work with radicals (adding or subtracting) they have to have the same radical expression. ex: 2 rad 3 + 4 rad 3 = 6 rad 3. If it helps, change the similar radicals to a variable. 2 rad 3 + 4 rad 3 2 x + 4 x = 6x and then substitute your radical back in for the variable. 6 rad 3 ---- rad 12 - 3 rad 3 Let's simplify radical 12. First, factor 12 into a perfect square, and a not perfect square.) Hint: we want it to be radical 3 to work with it... 3 times what is 12? rad 12 = sqrt(12) = sqrt(4*3) sqrt(4*3) = sqrt(4)*sqrt(3) sqrt(4) is just 2! We bring this to the "outside" of the radical. sqrt(4)*sqrt(3) = 2 sqrt(3) or 2 rad 3 rad 12 - 3 rad 3 2 rad 3 - 3 rad 3 (or 2x - 3x if it helps) We're left with: -1 rad 3, or just - rad 3 (negative radical 3)

3 minus -9 is 12.

It is 3/4 minus 1/3 is the same as 9/12 minus 4/12 = 5/12

12/3 minus 3/4 is 3 1/4 or 3.25