(√4x^2)(√36x)=2x(6√x)=12x√x
4x2-36x+81 (2x-9)(2x-9)
In real numbers there is no square root of -4x2 However, when using complex numbers where √-1 = i, then: √-4x2 = 2xi If you were asking, for example, with regard to the difference of two squares, eg y2 - 4x2, then you are actually finding the square root of 4x2 which is 2x, giving: y2 - 4x2 = (y + 2x)(y - 2x)
The expression is likely 4x2 - 36x +81 which is the same as (2x - 9)(2x - 9) or (2x - 9)2
(2x - 9)(2x - 9)
10x2 - 64 = 36x + 6x2Subtract 6x2 from both sides:4x2 - 64 = 36xSubtract 36x from both sides:4x2 - 36x - 64 = 0Divide everything by 4:x2 - 9x - 16 = 0Use the quadratic formula:x = (9±√(92-4(-16)))/(2)x = (9-√(145))/2 or x = (9+√(145))/2
4x2-36x+81 (2x-9)(2x-9)
81.
In real numbers there is no square root of -4x2 However, when using complex numbers where √-1 = i, then: √-4x2 = 2xi If you were asking, for example, with regard to the difference of two squares, eg y2 - 4x2, then you are actually finding the square root of 4x2 which is 2x, giving: y2 - 4x2 = (y + 2x)(y - 2x)
4x2 - 36x + 81 = 4x2 - 18x - 18x +81 = 2x(2x - 9) - 9(2x - 9) = (2x - 9)2
The expression is likely 4x2 - 36x +81 which is the same as (2x - 9)(2x - 9) or (2x - 9)2
(2x - 9)(2x - 9)
x = square root of 3.
10x2 - 64 = 36x + 6x2Subtract 6x2 from both sides:4x2 - 64 = 36xSubtract 36x from both sides:4x2 - 36x - 64 = 0Divide everything by 4:x2 - 9x - 16 = 0Use the quadratic formula:x = (9±√(92-4(-16)))/(2)x = (9-√(145))/2 or x = (9+√(145))/2
Only if the term under the radical (square root sign) can be simplified to a rational expression. For example, √(4x2).
(2x - i)(2x + i)where i is the square root of negative 1.x = 0.5i, -0.5i
Sqrt(24x4)/Sqrt(3x) = Sqrt(24x4/3x) = Sqrt(8x3) = Sqrt(4x2*2x) = 2x*sqrt(2x)
b. -4x2+20 = 4x2 = 4-20x2 = -16x = -4Note that -42 = -16 but (-4)2 in brackets = 16