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What is the answer to the sum of the squares of two consecutive positive integers is 3785 find the two integers?
Moniquemcfadden
The integers are 43 and 44. The answer can be found by representing the two consecutive numbers as "n" and "n+1".
n2 + (n+1)2 = 3785
n2 + (n2 + 2n + 1) = 3785
2n2 + 2n + 1 = 3785
2n2 + 2n - 3784 = 0
n2 + n - 1892 = 0
(n + 44) (n-43) = 0
n = -44, +43
The answer is restricted to positive values, so n = 43 and n+1 = 44
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∙ 14y ago
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