If you mean: 6x^2 +7x-3 then it is (2x+3)(3x-1) when factored
x2 + 6x = x*(x + 6)
(x-5)(x+11)
It can't be factored because the discriminant is less than zero.
4x2 - 6x - 12 = 2 (2x2 - 3x - 6) There are no integer roots, the approximate roots are 2.64 and -1.14
-6x^2 - 78x - 252 Improved answer: -6x+6x+7 When simplified = 7
x2 + 6x = x*(x + 6)
It is (x+5)(x+1) when factored
(x-5)(x+11)
It can't be factored because the discriminant is less than zero.
6x^2 + 5x + 1 = (3x +1) (2x + 1)
6x - 27xy= 3x(2 - 9y)=========
6x + 9x^3 = 3x*(2 + 3x^2)
6x^3 + 3x = 3x(2x^2 + 1)
2x(y - 3) + 7(y - 3) = (2x + 7)(y - 3)
This is a quadratic equation question in finding the possible values of x x2 - 6x = - 8 x2 - 6x + 8 = 0 Factorise the expression in the equation: (x-2)(x-4) = 0 Therefore: x = 2 or x = 4
4x2 - 6x - 12 = 2 (2x2 - 3x - 6) There are no integer roots, the approximate roots are 2.64 and -1.14
-6x^2 - 78x - 252 Improved answer: -6x+6x+7 When simplified = 7