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How do you tell if i have a xab or xbb coded transmission in my 2000 Pontiac grand prix gtp?
Read the tag on the transmission.
How is the power of power property rule and the power of a product property rule different?
(xa)b = xa*b = xab (xy)a = xaya
Used transmission 2000 Pontiac Grand Prix GTP?
Lots of luck trying to find one - they made 2 types - XAB and XBB There will be a tag, under the engine(trans) in about the center of the car to tell you which one you have. The dealer told us they are NOT interchangeable! However, they ARE interchangeable. The only issue would be that the XAB trans is not as stong as the XBB, specifically the sprag clutch. So while The only other cars produced with the XBB trans was the Buick Regal GS (supercharged), and the Buick Riviera (supercharged). The XAB appeared in all W-Body vehicles GM made, but if the engine isn supercharged, it will be a 4T65e NON-HD (as opposed to the 4T65e-HD in the blown cars). Without the HD option, the supercharged 3.8 will obliterate its bands and clutches, among other things.
In a gm ABCD the bisector of angle A also bisect BC at X. Prove tht AD2 AB?
AX bisects angle DAB so angles DAX and XAB are equal. .. .. .. .. .. .. .. .. (i)DA is parallel to CB and AX is an intercept.So angle DAX and AXB are alternate angles and therefore angles DAX and AXB are equal.Therefore, by (i) angles XAB and AXB are equal.Thus triangle BAX is isoscelestherefore AB = BX.BX = 1/2*BC = 1/2*AD (since ABCD is a parallelogram).Therefore AB = BX = AD/2.
What are some nine letter words with 1st letter A and 5th letter X and 6th letter A and 7th letter B?
According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 2 words with the pattern A---XAB--. That is, nine letter words with 1st letter A and 5th letter X and 6th letter A and 7th letter B. In alphabetical order, they are: affixable annexable
What are some seven letter words with 1st letter F and 3rd letter X and 4th letter A and 5th letter B?
According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 1 words with the pattern F-XAB--. That is, seven letter words with 1st letter F and 3rd letter X and 4th letter A and 5th letter B. In alphabetical order, they are: fixable
What are some seven letter words with 1st letter M and 3rd letter X and 4th letter A and 5th letter B?
According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 1 words with the pattern M-XAB--. That is, seven letter words with 1st letter M and 3rd letter X and 4th letter A and 5th letter B. In alphabetical order, they are: mixable
What rhymes with doo?
babble (dibble and) dabble drabble gabble grabble rabble scabble Scrabble (Trademark)near rhyme (spoken)addle astraddle dog-/up the creek without a/ paddle fiddle-faddle in the/side-/ saddle packsaddle raddle skedaddle straddle unsaddlejabble, gabble, maddle, Scabble, Snapple and rabble
In a parallelogram show that bisectors of adjacent angles intersect at right angles?
Label the parallelogram ABCD (with AB parallel to DC, AD parallel to BC) and the point where the angle bisectors of DAB and ABC meet X. It is needed to be shown that angle AXB is 90o.Call angle DAB a and angle ABC b. Then the bisectors of these angles are 1/2a and 1/2b.First note that for a parallelogram, opposite angles are equal, ie:ADC = ABC = aDAB = DCB = bAlso, the sum of all angles in a quadrilateral (and a parallelogram is one) in 360o. Thus:360o = DAB + ABC + BCD + CDA360o = a +b + a + b360o = 2a +2bOr dividing by 2:180o = a + band again by 2:90o = 1/2a + 1/2b - [1]Now consider triangle AXB. Angle XAB = 1/2b, XBA = 1/2b. So angle:AXB = 180o - (XAB + XBA)AXB = 180o - (1/2a + 1/2b)AXB = 180o - 90o (As shown in [1] above)AXB = 90oThus the bisectors of adjacent angles of a parallelogram meet at right angles.Opposite angles of a parallelogram can be shown to be equal by extending sides AB and DC and then using corresponding and alternate angles.Alternatively, adjacent angles of a parallelogram can also be shown to sum to 180o by extending line AB (to any point Y beyond B) and using that DAY and CBY are corresponding angles and that ABC and CBY sum to 180o since ABY is a straight line.
What is the value of a Commonwealth of Australia Twenty Dollar note with the prefix XAB?
The "Commonwealth of Australia" 10 Dollar paper note was issued in 1966, 1967, 1968 and 1972 and are no longer in circulation. After these issues, "Commonwealth of" was dropped. If it has been circulated and there is nothing unusual about it, it might fetch up to face value or a little more. If there is something unusual about it like the first of a series, all serial digits the same, a "Star" note, a notable defect in printing, etc., and it is still in very good condition or better, it might fetch up to $850 AUD or more. If it is uncirculated and there is nothing unusual about it, and in mint condition, it might fetch up to $220 AUD. If there is something unusual about it as previously described, it might fetch up to $14,000 AUD or more.
Suppose you would like to divide a file per 50 lines and save them in separate files. Which of the following is used to do this?
Any implementation of linux or unix will have a command (or program) called split.split ----lines=50 inputfileamesplits a file in 50 line chunks. The result is a set of files named xaa xab xac ...split ----lines=50 inputfileame outfilenamesplits a file in 50 line chunks. The result is a set of files named outfilenameaa outfilenameab outfilenameac ...split ----lines=50 --suffix-length=4 inputfileame outfilenamesplits a file in 50 line chunks. The result is a set of files named outfilenameaaaa outfilenameaaab outfilenameaaac ...A version of this program is freely available for the windows platform, and other platforms.There are other programs that can do the same thing, freely available by searching the internet.
Average weight of 100 screws in box 'A' is 10.4gms it is mixed withed with150 screws of box 'B' average weight of mixed screws is 10.9 gms find the average weight of screws of box 'B'?
Let 'x' be the total weight of 100 screws in box 'A' therefore, average weight of 100 screws in box 'A' = (x / 100) = 10.4 => x = 100*10.4 = 1040 gms ............ (1) Let 'y' be the total weight of 150 screws in box 'B', therefore, average weight of 150 screws in box 'B' = (y / 150) .......... (2) After mixing 100 screws of 'A' and 150 screws of 'B', average weight of 250 screws = (x+y)/250 = 10.9 => x+y = 250*10.9 = 2725 => 1040+y = 2725 => y = 2725 - 1040 = 1685 => total weight of 150 screws of box 'B', y = 1685 gms Substitute y = 1685 in eqn (2), => average weight of screws of box 'B' = 1685/150 = 11.23 gms (approx) Hence, average weight of screws of box 'B' = 11.23 gms SHORT ANSWER """"""""""""""""" Given data: No. of screws in box 'A', NA = 100 No. of screws in box 'B', NB = 150 Average weight of 100 screws in box 'A', XA = 10.4 gms Average weight of mixed screws, XAB = 10.9 gms Average weight of 150 screws in box 'B', XB = ? Therefore, XAB = (NA XA + NB XB) / (NA + NB) 10.9 = (100*10.4 + 150XB) / (100+150) 10.9 = (1040 + 150XB) / 250 10.9*250 = 1040 + 150XB 2725 = 1040 + 150XB 2725 - 1040 = 150XB 1685 = 150XB XB = 1685/150 = 11.23 gms XB = 11.23 gms - Ratnakar Sharma
