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What is the area bounded by the graphs of fx and gx where fx equals xcubed and gx equals 2x-xsquared?
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∙ 14y ago
What_is_the_area_bounded_by_the_graphs_of_fx_and_gx_where_fx_equals_xcubed_and_gx_equals_2x-xsquared
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∙ 14y ago
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Square root of x to the sixth power?
x3.
How do you factor xcubed-1?
(x - 1)(x2 + x + 1)
What is xcubed minus 7xsquared plus 8x plus 16 divided by x plus 1?
Answer is x2 -6x+14 with remainder 2
What is -2(7xcubed times Ytothe power of 5 plus 8Yto the power of 5 times xcubed)?
-30xcubed times y to the power of 5
What is -2(7xcubed times Ytothe power of 5 plus 8Yto the power of 5 times xcubed?
-30xcubed times y to the power of 5
What is the volume of a cube with a hight of 3 feet?
A cube has equal sides. If one side is equal to 3 feet.... The equation: V = X*X*X (or Xcubed)
4xsquared plus xcubed plus 3x plus 7y plus 2xcubed is equal to?
4X2+X3+3X+7Y+2X3 can only be simplified to 3X3+4X2+3X+7Y, because X3 and 2X3 are the only like terms.
What is x minus 1 cubed?
xcubed-1 Answer::(X-1)(Xsquared+X+1) when you factor xcubed minus a number its the same thing as x cubed minus y cubed and x cubed minus y cubed factors to:: (x-y)(xsquared+xy+y squared) the first factor, (x-y), is the cubed root of the first and the cubed root of the second, so in the answer i have (x-1), which is x cubed minus one cubed :) the second factor, (xsquared+xy+ysquared), you take the first number squared, Xsquared, then the first and second one multiplied together, XY, and then the second number squared, Ysquared, so in the answer i have (xsquared+x+1), which is x squared, then x times 1 which is just x, and positive 1, which is negative 1 squared :) x^3 - 1
Using the remainder theorum determine the remainder when xcubed PLUS 3xsquared - x - 2 is divided by x PLUS 3 TIMES x PLUS 5 theres brackets around x PLUS 3 and seperatly around x PLUS 5?
(x^3 + 3x^2 - x - 2)/[(x + 3)(x + 5) in this case you can use the long division to divide polynomials and to find the remainder of this division. But you cannot use neither the synthetic division to divide polynomials nor the Remainder theorem to determine the remainder. You can use both the synthetic division and the Remainder theorem only if the divisor is in the form x - c. In this case the remainder must be a constant because its degree is less than 1, the degree of x - c. The remainder theorem says that if a polynomial f(x) is divided by x - c, then the remainder is f(c). If the question is to determine the remainder by using the remainder theorem, then you are asking to find the value of f(-3) when you are dividing by x + 3, or f(-5)when you are dividing by x + 5 . Just substitute -3 or -5 with x into the dividend x^3 + 3x^2 - x - 2, and you can find directly the value of the remainder. f(-3) = (-3)^3 + 3(-3)^2 - (-3) - 2 = -27 + 27 + 3 - 2 = 1 (remainder is 1) f(-5) = (-5)^3 + 3(-5)^2 - (-5) - 2 = -125 + 75 + 5 - 2 = -47 (remainder is -47).
