36
That would depend on the length of the rectangle which has not been given but the area of a rectangle is length times width
The area of a rectangle is always length multiplied by width. Therefore, the area of the mentioned rectangle is 36cm2.
Length: 4; Width: 5 or Length: 5; Width: 4
Area = Length *Width = 28*4 = 112 sq cm
length: 22.5
That would depend on the length of the rectangle which has not been given but the area of a rectangle is length times width
Length = 4, Width = 2
The area of a rectangle is always length multiplied by width. Therefore, the area of the mentioned rectangle is 36cm2.
Length: 4; Width: 5 or Length: 5; Width: 4
Area of the rectangle = 36 =Length * Width Assume Width= a Hence Length = 4*a =4a Area = a*4a =36 Therefore, a*a =9 Hence a =3 =Width
Area = Length *Width = 28*4 = 112 sq cm
length: 22.5
width=16 and length=20
A rectangle with width 4 can have any length!
Area = length x width, so length = area/width = 116/4 = 29 yds
Let x be the width of the rectangle. Then the length is 3x. The area of the rectangle is 3x * x = 3x^2, which also has to be 48. Solving for x, we get that the width is 4, and the length is 12.
Approximately 5.2115 and 9.2115