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This hexagon is made of 6 equilateral trianges of side length 8 inches. Height of such a triangle is SQRT(8^2 - 4^2) = SQRT(48) = 6.93 inches. Area of one triangle = 4 x 6.93 = 27.71 square inches.

Answer = 6 * 27.71 = 166.28 square inches

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Q: What is the area of a regular hexagon with the given measurement of 48 inch perimeter?
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What shape has the same perimeter but not the same area?

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Related questions

What is the area of a regular hexagon with the given measurement of 48-inch perimeter?

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The area of a given hexagon is equal to the area of an equilateral triangle whose perimeter is 36 inches Find the length of a side of the regular hexagon?

The area of a given hexagon is equal to the area of an equilateral triangle whose perimeter is 36 inches. Find the length of a side of the regular hexagon.Click once to select an item at the bottom of the problem.


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Given the perimeter of a regular hexagon, it is better to use the side length: 6 inches, rather than the apothem of 5.2 inches because the latter is he rounded value of 3*sqrt(3) which is 5.196152... rather than 5.2. Based on the length of the sides, the area is approx 93.53 sq inches. [The apothem would have given 93.67 sq inches.]


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How do you do find the area of a hexagon?

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