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14*8 = 112 sq cm

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Q: What is the area of a rhombus whose diagonals are 14 cm and 8 cm?
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What is the area of a rhombus with the diagonals 14 cm and 8 cm?

The area is 56 cm2


What is the area of a rhombus if ac is 14cm and db is 8cm?

AC and DB must be the diagonals of the rhombus, because the sides are all equal. Area = product of the diagonals. = 14 x 8 = 112


What is the area of diagonals of 14 feet and 10 feet?

If this is a rhombus then the area is half the product of the diagonals - 10 x 14 = 140. Half of 140 = 70, so the area is 70 square feet.


What is the a area of a rhombus with diagonals of 10 feet and 14 feet?

It is: 0.5*10*14 = 70 square feet


What is the area of a rhombus if ac equals 14 bd equals 17 and ab equals 11?

The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonalsIn your case, that's 14 x 17 / 2 = 119


What is the area of this rhumbus ac14cm db8cm?

If those are the diagonals of the rhombus then its area: 0.5*14*8 = 112 square cm


What is the formula for calculating volume of rhombus?

A rhombus has four equal sides and its diagonals bisect each other at right angles. The area of the rhombus ia given by following formula where x and y are the lengths of the diagonals of the rhombus...A=1/2xy. Example, the diagonals of a rhombus where x = 26 and y = 14....A=1/2xy...=1/2 x 26 x 14 which equals 182. so the area of the rhombus is 182 square inches, miles or whatever measurement you are dealing with the 3d annaloge to a rhombus is the rhomboid, the formula to fin dteh volume of that is A . (B x C).


What is the area of this rhombus ac14cm db8cm?

If ac and bd are diagonals then area of rhombus = 1/2 x ac x bd Area = 1/2 x 14 x 8 cm2 = 56 cm2


What is the area of a rhombus with diagonals of 10 feet and 14 feet?

The diagonals of a rhombus intersect at right angles and bisect each other.... this should be the only tip you need. Good luck with your homework. how bout u be a little bit more blunt and just say the awnser?? A+:70ft^2


What is the perimeter of a rhombus whose diagonals add up to 24.5 cm and has an area of 73.5 square cm showing all work?

Let the diagonals be x and yIf: x+y = 24.5 then y = 24.5-xIf: 0.5xy = 73.5 then 0.5x(24.5-x) = 73.5So: 24.5x -x^2 -147 = 0Solving the above quadratic equation: x = 14 or 10.5The rhombus will consist of 4 right angles of base 5.25 and height 7Using Pythagoras' theorem each side of the rhombus is 8.75 cmTherefore its perimeter is: 4*8.75 = 35 cm


What is the area of a ABCD rhombus when angle AC equals 14 and angle BD equals 17?

An angle is not normally defined by two characters. Also, a rhombus cannot have two angles whose measures are 14 and 17: any two angles MUST be complementary or equal.


How many diagonals in heptagon's?

In a heptagon there is 14 diagonals