14*8 = 112 sq cm
AC and DB must be the diagonals of the rhombus, because the sides are all equal. Area = product of the diagonals. = 14 x 8 = 112
The diagonals of a rhombus intersect at right angles and bisect each other.... this should be the only tip you need. Good luck with your homework. how bout u be a little bit more blunt and just say the awnser?? A+:70ft^2
14 diagonals
A undecagon has 44 diagonals. A dodecagon has 54 diagonals. An octagon has 20 diagonals. A heptagon has 14 diagonals.
112
The area is 56 cm2
AC and DB must be the diagonals of the rhombus, because the sides are all equal. Area = product of the diagonals. = 14 x 8 = 112
If this is a rhombus then the area is half the product of the diagonals - 10 x 14 = 140. Half of 140 = 70, so the area is 70 square feet.
It is: 0.5*10*14 = 70 square feet
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonalsIn your case, that's 14 x 17 / 2 = 119
If those are the diagonals of the rhombus then its area: 0.5*14*8 = 112 square cm
A rhombus has four equal sides and its diagonals bisect each other at right angles. The area of the rhombus ia given by following formula where x and y are the lengths of the diagonals of the rhombus...A=1/2xy. Example, the diagonals of a rhombus where x = 26 and y = 14....A=1/2xy...=1/2 x 26 x 14 which equals 182. so the area of the rhombus is 182 square inches, miles or whatever measurement you are dealing with the 3d annaloge to a rhombus is the rhomboid, the formula to fin dteh volume of that is A . (B x C).
If ac and bd are diagonals then area of rhombus = 1/2 x ac x bd Area = 1/2 x 14 x 8 cm2 = 56 cm2
The diagonals of a rhombus intersect at right angles and bisect each other.... this should be the only tip you need. Good luck with your homework. how bout u be a little bit more blunt and just say the awnser?? A+:70ft^2
Let the diagonals be x and yIf: x+y = 24.5 then y = 24.5-xIf: 0.5xy = 73.5 then 0.5x(24.5-x) = 73.5So: 24.5x -x^2 -147 = 0Solving the above quadratic equation: x = 14 or 10.5The rhombus will consist of 4 right angles of base 5.25 and height 7Using Pythagoras' theorem each side of the rhombus is 8.75 cmTherefore its perimeter is: 4*8.75 = 35 cm
An angle is not normally defined by two characters. Also, a rhombus cannot have two angles whose measures are 14 and 17: any two angles MUST be complementary or equal.
In a heptagon there is 14 diagonals