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Lets take one side's length as 'x' then otherside equals (x+4) Addition of 'x'squared and (x+4)squared equal to 20*20 x*x + (x+4)(x+4)=20*20 Solving algebraic expression x =12 x+4=16 area=96

Another Answer:-

1 Let the sides be x+4 and x

2 Using Pythagoras: (x+4)2+x2 = 202 which transposes to 2x2+8x-384 = 0

3 Solving the above quadratic equation gives x a positive value of 12

4 Therefore the sides are 12+4 = 16 cm and 12 cm

5 Area = 0.5*16*12 = 96 square cm

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Q: What is the area of a right angle triangle when one side is greater than the other side by 4 cm and has an hypotenuse of 20 cm showing all work?
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