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What is the area of a shape with 900 sides a the same length 11 inches?
Wiki User
∙ 12y ago
I will assume that it is a regular polygon (it isn't given if the interior angles are the same, but then the answer would not be a constant).
900 sides means 900 vertices which means 900 lines from the center and 900 congruent isosceles triangles formed by these lines. Now the polygon is 900*area of one triangle. The vertex of each isosceles triangle is 360o over 900, or 2/5o. We know the base to be 11 inches and find the height to be about 27.1 inches (using 5.5/tan(.2)). The area of one triangle is about 149.23. The area of the entire polygon is about 134305 square inches.
Wiki User
∙ 12y ago
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