The information given describes a square and not a trapezium.
Area of the square = 3*3 = 9 square cm
If the two parallel side of the trapezium are a and b and height of the trapezium (the distance between the parallel sides) is h then the area is given by:Area = 1/2 (a + b) x hHalf the sum of the lengths of the parallel sides times the distance between them.
The area of a trapezium is found because: 0.5*(sum of parallel sides)*height = area
Let the two parallel sides be a and b, and the distance between them, the height of the trapezium, be h. Then: area of trapezium = 1/2 (a+b) h That is half the sum of the two parallel sides times the height of the trapezium.
If the lengths of the parallel sides are x and y units, and the height is h units, then the area = 1/2*(x + y)*h square units.
If the lengths of the two parallel sides are a and b, and the height of the trapezium (the distance between them) is h, then area_of_trapezium = 1/2 (a + b) h that is half of the sum of the lengths of the two parallel sides multiplied by the distance between them.
If the two parallel side of the trapezium are a and b and height of the trapezium (the distance between the parallel sides) is h then the area is given by:Area = 1/2 (a + b) x hHalf the sum of the lengths of the parallel sides times the distance between them.
A trapezium has a pair of parallel sides of different lengths so in order to find its 2nd parallel side the information given must include its height.
The area of a trapezium is found because: 0.5*(sum of parallel sides)*height = area
Let the two parallel sides be a and b, and the distance between them, the height of the trapezium, be h. Then: area of trapezium = 1/2 (a+b) h That is half the sum of the two parallel sides times the height of the trapezium.
Call the two parallel sides a and b and find their average, a+b divided by 2. This is the average of the horizontal lengths. Now multiply this by height, the height, and you have the area!It's easy!
5x3 + ½*(7-5)*3 = 15+3 = 18 cm²
If the lengths of the parallel sides are x and y units, and the height is h units, then the area = 1/2*(x + y)*h square units.
If the lengths of the two parallel sides are a and b, and the height of the trapezium (the distance between them) is h, then area_of_trapezium = 1/2 (a + b) h that is half of the sum of the lengths of the two parallel sides multiplied by the distance between them.
Atrapezoidor trapezium is a quadrilateral with two parallel sides. These two sides are called the bases. Find the average of the lengths of the bases andmultiplyby the perpendicular distance between the parallel sides (the height).bases have lengths a and b, height is h: A = h(a+b)/2
Area of a trapezium = 0.5*(sum of parallel sides)*height
Area = 1/2*(sum of the parallel sides)*height
has two parallel sideshas four straight linesThe area of the trapezium is given by the following formula where a and b are the lengths of the parallel sides and h is the perpendicular distance between the parallel sides.