Area = 0.5*base*height
Note that the given dimensions would not form a triangle
Area 51.
180 cm2
A right triangle has a hypotenuse of 12cm and a leg that is 9cm the other leg would be 7.94. This is a math problem.
This is not an equilateral triangle.
Since an isosceles triangle can be represented by two right triangles back to back, you can utilize the pythagorean theorum to solve this example. Specifically: 18cm/2 = 9cm = 1 leg of right triangle (A) 24cm = hypotenuse of right triangle (C) A squared + B squared = C squared Altitude = B = square root of (C squared - A squared) = approximately 19.875
18cm 2
The area is 108cm2
Area 51.
180 cm2
add 9cm to10cm and you come up with 19cm is ths correct?
27cm squared
An arbitrary large number is the answer for anyrectangle, up to that with a length of 9cm, and 0cm as the width will have a perimeter of 18cm.Similarly, any rectangle up to that with sides 0cm long, and a width of 9cm will have your 18cm perimeter.
2
45 square cm
The area of a parallelogram with base 18cm and perpendicular height 18cm is 324 cm2
1/2b*h 180 cm^2
It is: 0.5*9*6.5 = 29.25 square cm