12 units
Yes, but only if the parallelogram has right angled vertices.
Area circle: π × radius² Area triangle: ½ × base × height Area Parallelogram: base × height Area: Rectangle: length × width In a triangle, the base is any side between two vertices and the height is the perpendicular distance from this side to the third vertex. In a parallelogram the base is any side. The height is the perpendicular distance between this side and the side parallel to it.
The Area of a parallelogram is Area=base times height.
The area formula for the parallelogram is related to the area formula for a rectangle because you can make the parallelogram into a rectangle to find the area.
Area of a parallelogram in square units = base*height
To find the area of a parallelogram, multiply the base by the height.
The area of the parallelogram is quadrupled.
I don't know about the relation in the perimeters of a triangle and a parallelogram but if a triangle is on the same base on which the parallelogram is and the triangle is between the same parallel lines of the parallelogram, then the area of the triangle will be half the area of the parallelogram. That is, area of a triangle = 1/2 area of a parallelogram if the triangle is on the same base and between the same parallel lines.
If the heights and bases are the same, then the triangle is half the area of the parallelogram.
The area of the parallelogram is quadrupled.
63mm2. The area of a parallelogram is just LxW.
The formula for area of a parallelogram is bh. Base times height.