Best Answer

y = x2 - 5x

The integral of [ y dx ] = x3/3 - 5x2/2 + C

At x=0, the integral = 0

At x=5, the integral = 125/3 - 125/2 = -20.8333

At x=6, the integral = 72 - 90 = -18

At x = -2, the integral = -8/3 - 10 = -12.6666

a). from 0 to 5, the area is -20.8333 (20.8333 below the x-axis)

b). from 0 to 6, the area is -18.

c). from -2 to +5, the area is (-20.8333 + 12.6666) = +9.8333

Q: What is the area of the region between y equals x2 -5x and the x axis a from 0 to5 b from 0 to 6 cfrom-2 to5?

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0.0606

39.0625 is.

Length times width equals area

0.908 approx.

Look in any standard normal distribution table; one is given in the related link. Find the area for 2.43 and 1.52; then take the area for 2.43 and subtract the area for 1.52 and that will be the answer. Therefore, .9925 - .9357 = .0568 = area under the normal distribution curve between z equals 1.52 and z equals 2.43.

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39.0625 is.

0.0606

I think cultural area is a bigger amount of space than cultural region but I'm not sure.

Length times width equals area

1

0.908 approx.