Area = L*W
Area = 14* (5x-3)
Area = 60x-42
The surface area is L*B where L is the length of the rectangle and B is the breadth.
In order to find the area of a rectangle, you must follow the formula A= l x w where A is area, l is length, and w is width.
Any rectangle with a length and width that multiply together to equal 14. L=14 W=1, or L=7 W=2, or L=10, w=1.4 or L=5 w=2.8 etc
Let L be the length of the rectangle. Since the length of the side of the square is the same as the width of the rectangle and the width of the rectangle is its length minus 6, the length of the side of the square is (L-6) and the area is (L-6)2. Since the width of the rectangle is its length minus 6, its area is L(L-6). Here is some of the work: 176 = (L-6)2 + L(L-6) 176 = (L-6)(L-6) + L(L-6) 176 = L2 - 6L - 6L + 36 + L2 - 6L 176 = 2L2 - 18L + 36 140 = 2L2 - 18L 70 = L2 - 9L 70/L = L - 9 (9L + 70)/L = L L = (9L+70)/L L2 = (9L+70) L = sqrt(9L+70) According to WolframAlpha (www.wolframalpha.com), L=14. (But don't say L; use x). The length of the side of the square is 8 m, which is also the width of the rectangle; the length of the rectangle is 14 m; the area of the square is 64 m2; and the area of the rectangle is 112 m2.
the formula for a rectangle is L x W where L is length and W is width.
First of all to correct . The area is NOT 14 feet , that is a liner measurement, but 14 sq.ft. (square feet) #Hence A = lb = 14 sq.fr. P = 2( l + b) = 18ft. b = 14/l & l + b = 9 Substitute (14/l) + l = 9 Multiply though by 'l' 14 + l^2 = 9l l^2 - 9l + 14 = 0 Factor ( l - 7)(l - 2) = 0 Hence l = 7 ft. and l = 2ft Common sense dictates that the length is 7 ft.
Area of rectangle is l x b. Where l is length and b is breath of the rectangle.
Area of a rectangle: a = l * w
Area of a rectangle in square units = length*width
The surface area is L*B where L is the length of the rectangle and B is the breadth.
In order to find the area of a rectangle, you must follow the formula A= l x w where A is area, l is length, and w is width.
Any rectangle with a length and width that multiply together to equal 14. L=14 W=1, or L=7 W=2, or L=10, w=1.4 or L=5 w=2.8 etc
Let L be the length of the rectangle. Since the length of the side of the square is the same as the width of the rectangle and the width of the rectangle is its length minus 6, the length of the side of the square is (L-6) and the area is (L-6)2. Since the width of the rectangle is its length minus 6, its area is L(L-6). Here is some of the work: 176 = (L-6)2 + L(L-6) 176 = (L-6)(L-6) + L(L-6) 176 = L2 - 6L - 6L + 36 + L2 - 6L 176 = 2L2 - 18L + 36 140 = 2L2 - 18L 70 = L2 - 9L 70/L = L - 9 (9L + 70)/L = L L = (9L+70)/L L2 = (9L+70) L = sqrt(9L+70) According to WolframAlpha (www.wolframalpha.com), L=14. (But don't say L; use x). The length of the side of the square is 8 m, which is also the width of the rectangle; the length of the rectangle is 14 m; the area of the square is 64 m2; and the area of the rectangle is 112 m2.
the formula for a rectangle is L x W where L is length and W is width.
Perimeter = 2*(Length + Width) So 36 = 2*(L+4) => 18=L+4 => L = 14 ft So area = Length * Width = 14*4 = 56 sq ft
MULTIPLICATION area for a rectangle is A = L * W * H where, A = area of rectangle L = Length of rectangle W = width of rectangle H = height of rectangle The dimensions of a rectangle (L, W, and H) are interchangeable because they are being multiplied together and hence each side of the rectangle can be arbitrarily assigned to a dimension.
Let's take a look at this problem.Rectangle Perimeter = 2(l + w)Rectangle Perimeter =? 2(2l + 2w)Rectangle Perimeter =? (2)(2)(l + w)2(Rectangle Perimeter) = 2[2(l + w)]Thus, we can say that the perimeter of a rectangle is doubled when its dimensions are doubled.Rectangle Area = lwRectangle Area =? (2l)(2w)Rectangle Area =? 4lw4(Rectangle Area) = 4lwThus, we can say that the area of a rectangle is quadruplicated when its dimensions are doubled.