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Use the definition of "average", as follows.Add all the numbers up. Call the result "sum". Then count how many numbers there are, and divide "sum" by that number.
In this particular case, the interval between any two consecutive numbers is the same (an arithmetic sequence); in this case, you can use the following shortcut: the average is simply the number in the middle. (And if there are an even number of numbers, take the average between the two numbers in the middle.)
Wiki User
∙ 7y ago
Wiki User
∙ 7y agoThe average of the above numbers is 18
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What is the nth term for the sequence 18 23 28 33 38?
The 'n'th term is [ 13 + 5n ].
What is the nth term for 8 13 18 23?
It is: 5n+3 and so the next term is 28
What is 3 plus 8 plus 13 plus 18 plus 23 plus 28?
The sum is 93.
What comes next in the pattern 3 8 13 18 23 28 30 31 32?
hello
Which number when you divide by 5 has a remainder of 3?
18 / 5 = 3 remainder 3 Answer: 18 Other possible correct answers are: 8 13 23 28 3
What is the sequence for 5N plus 3?
8, 13, 18, 23, 28, etc.
If the average of these four numbers is 21 find the missing number from 12 18 28?
23
What is the nth term of the sequence 18 23 28 33 38?
The 'n'th term is [ 13 + 5n ].
What is the the nth term of the sequence 18 23 28 33 38?
The 'n'th term is [ 13 + 5n ].
What is the nth term for the sequence 18 23 28 33 38?
The 'n'th term is [ 13 + 5n ].
What is the nth term for 8 13 18 23?
It is: 5n+3 and so the next term is 28
What comes next in the pattern 3 8 13 18 23 28 30 31 32?
hello
What is 3 plus 8 plus 13 plus 18 plus 23 plus 28?
The sum is 93.
What number is halfway between 18 and 28?
Halfway between 18 and 28 is (18 + 28) ÷ 2 = 23.
What is the nth term of 8 13 18 23 28?
t{n} = (3n⁵ - 45n⁴ + 255n³ - 675n² + 1022n - 240)/40 This gives t{1..5} = {8, 13, 18, 23, 28} and continues t{6...} = {42, 92, 232, 552, 1187, ...} However, your teacher probably wants the much simpler: t{n} = 5n + 3 Which also gives t{1..5} = {8, 13, 18, 23, 28} but continues t{6...} = {33, 38, 43, 48, ...} There are infinitely many formulae that can be given to give the terms t{1..5} = {8, 13, 18, 23, 28}; they all differ in what terms follow. Which means that any formula for the nth term of t{1..5} = {8, 13, 18, 23, 28} is ONLY valid for n = 1, 2, ..., 5 as 5 terms have been given.
What does 23-5 equal?
28
What is the average of 8 18 and 28?
18
