it is 33; you can add all up and divide by 17, or simply add first and last and divide by 2
The average of all the integers in that interval is the same as the average of the extremes, in this case, just take the average of 25 and 41.
The average is 33.
42 + 52 = 16 + 25 = 41
(25+26+27+28+29+30+31+32+33+34+35+36+37+38+39+40+41) / 17 => 561/17 => 33 The Answer
41-25 = 16
There are no consecutive even integers totaling 123 but there are two combinations of odd/even integers. They are 39, 41 and 43 as well as 40, 41 and 42.
There are 3598 numbers between 10000 and 99999 which are divisible by 25. They are elements of the set of numbers of the form 25*k, where k is an integer between 41 and 3999 (inclusive).
The average of the integers 25 and 41 is 33. Average is found by adding up the integers and dividing that number by the number of integers that were added together. So, 25+41=66, then 66/2=33.
It is 33.
It is 33.
66
It is 33.
33
66
It is 41 - 25 = 16
41 is between the integers 40 and 42.
42 + 52 = 16 + 25 = 41
33. ( how i got it 25+41= 66; 66/2= 33)
Since 16 + 25=41, we know the integers are 4 and 5.