79+82+93+91+100=445/5=89
79
The prime numbers between 50 and 100 are 53, 59, 61, 67, 71, 73, 79, 83, 89, and 97.
Average of three test scores is 84 can be written (x+y+z)/3=84. If you know two of the scores then (79+93+z)/3=84, so to solve for z, 79+93+z=84*3 z=252-79-93 z=80 The first test score was 80
The average of 79, 84, 82, and 87 is 83.
79 is the average
79.
79
53 59 61 67 71 73 79 83 89 97.
The prime numbers between 50 and 100 are 53, 59, 61, 67, 71, 73, 79, 83, 89, and 97.
Average of three test scores is 84 can be written (x+y+z)/3=84. If you know two of the scores then (79+93+z)/3=84, so to solve for z, 79+93+z=84*3 z=252-79-93 z=80 The first test score was 80
To find the average, add the scores and divide the sum by how many scores you are adding: 81 + 76 + 91 + 73 + 79 = 400 ÷ 5 = 80.
The prime numbers between 10 and 100 are 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, and 97.
yes it is
The arithmetic mean is 79.
If it is a small list of scores, like 6 of them, write them in a list, for example: 96, 87, 80, 79, 75, 75 Find the 'middle' which will occur BETWEEN two numbers 96, 87, 80 (middle) 79, 75, 75. Average the two numbers on either side of the 'middle.' In this example (80 + 79) / 2 = 79.5 If the list is larger find the middle by dividing the total number of cases by 2. In this example 6 / 2 = 3. The median will be the middle BETWEEN the 3rd and 4th score. (Average the 3rd and 4th score)
score y 87
92.5 is the average.