avg. speed = distance traveled / time
so, 100 km / 1.25 hours = 80 km/hr
Average speed = total distance divided by total time (100 km) divided by 2 hours = average speed = 50km/h.
your average speed is 50 kilometers per
Answer: 1 3/5 hours or 1 hour and 36 minutes Explanation: Distance traveled = Speed * time or solved for time is time = distance traveled / speed Plug in known values for speed and distance traveled and you will get the time it took.
AnswerDetermine the distance traveled and divide by the time it took to cover that distance. If one travels 100 miles in two hours, one averaged 100/2 miles per hour or 50 miles/hour.Example:A car travels between 2 towns 60 miles apart in 2 hours. What is its average speed?Answer:average speed = distance/time Therefore, the average speed of the car is 60 miles/2 hours = 30 miles/hour. last update November 22, 2005 by JL Stanbroughhttp://www.batesville.k12.in.us/physics/phyNet/mechanics/Kinematics/AveSpeed.html
50 KM per hour.
100 miles per hour.
Average speed = total distance divided by total time (100 km) divided by 2 hours = average speed = 50km/h.
your average speed is 50 kilometers per
100 Km.
Average speed = distance/time = 100/4 miles per hour = 25 mph.
100 kilometers per hour or 124 miles per hour
40mph
50km/hr
Answer: 1 3/5 hours or 1 hour and 36 minutes Explanation: Distance traveled = Speed * time or solved for time is time = distance traveled / speed Plug in known values for speed and distance traveled and you will get the time it took.
Speed = Distance/Time = 100 km / 4 hours = 100/4 km per hour = 25 kph
Its speed which is 300/3 = 100 km per hour
AnswerDetermine the distance traveled and divide by the time it took to cover that distance. If one travels 100 miles in two hours, one averaged 100/2 miles per hour or 50 miles/hour.Example:A car travels between 2 towns 60 miles apart in 2 hours. What is its average speed?Answer:average speed = distance/time Therefore, the average speed of the car is 60 miles/2 hours = 30 miles/hour. last update November 22, 2005 by JL Stanbroughhttp://www.batesville.k12.in.us/physics/phyNet/mechanics/Kinematics/AveSpeed.html