use Archimedis' law- take a known volume of water in a vessel filled upto the brim and immerse the object that you want to measure the volume inside the vessel without giving any pressure and measure the volume of the water overflowed. that will give you the volume of the object(an approximate value)
yes you can use a balance to measure the volume of an irregular shaped solid.
The volume of an irregularly shaped solid can be measured by placing the solid in a known quantity of water in a container with measurement markings. Take the new volume and find the difference between this and the old volume. This is the volume of your irregularly shaped solid.
A balance is used to measure the mass of an irregularly shaped solid.
Yes you can.You can measure the solid by putting it into a gradruated cylinder.The height of the water shows you how much volume the solid has. fun is at www.qyue.webs.com
When you are trying to find the volume of an irregularly shaped object.
This is the Archimedes principle.
well, for an irregularly shaped object it is a eureka can or a graduated cylinder, but for a regularly shaped object it is a simple formula: Length*Width*Height. I am 10 years old and learned that in science class.
When an object is immersed in water the volume of water displaced is equal to the volume of that object as discovered by Archimedes.
By water displacement. Pour a certain volume of water into a graduated cylinder, and record that volume. Now, place the irregularly shaped object into the cylinder, and record the level to which the water now rises. Take the difference between those two volumes, and you now have the volume of your irregularly shaped object.
Use a measuring cylinder with water in it. Note down the volume of water in the cylinder, then add the solid. Note down the new volume and subtract the first value from the second to get the volume of the solid.
A cube is hardly an irregularly shaped object. Measuring it is the defining term of area and volume. A cube is defined as having twelve sides, all lengths uniform, all angles right angles. If the length of any side is 'a' then area = 6*a*a volume = a*a*a
Immerse it in water and its volume is equal to the volume of water displaced