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1111 converted from binary (base 2) to decimal (base 10) is 15

When you expand the steps...

1111 binary

= (1 X 2^3) + (1 X 2^2) + (1 X 2^1) + (1 X 2^0)

= 8 + 4 + 2 + 1

= 15

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13y ago
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10y ago

111110 = 10 001 010 1112

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Q: What is the decimal equivalent of 1111 in binary?
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How do you represent a negative number in Binary Coded Decimal?

All I know is that when a number is negative, you convert the decimal into binary and if it is negative you put 1111 before the binary digits.


What is the binary equivalent of 8?

8 in decimal is 1000 in binary


The binary equivalent of decimal 6 is?

The number 6 in binary is 110


What is the Largest real number that can be stored in binary using 16 bits Where 1 bit is used for the sign 5 bits for the characteristics and 10 for the Mantissa?

In binary the largest number (using IEEE binary16) representable would be: 0111 1111 1111 1111 (grouping the bits in nybbles* for easier reading). This is split as |0|111 11|11 1111 1111| which represents: 0 = sign 111 11 = exponent 11 1111 1111 = mantissa. Using IEEE style, the exponent is offset by 011 11, making the maximum exponent 100 00 This is scientific notation using binary instead of decimal. As such there must be a non-zero digit before the binary point, but in binary this can only ever be a 1, so to save storage it is not stored and the mantissa effectively has an extra bit, which for the 10 bits specified makes it 11 bits long. Thus the mantissa represents: 1.11 1111 1111 This gives the largest number as: 1.1111 1111 11 × 10^10000 (all digits are binary, not decimal.) This expands to 1 1111 1111 1100 0000 (binary) = 0x1ffc0 = 131,008 Note that this is NOT accurate in storage - there are 6 bits which are forced to be zero, making the number only accurate to ±32 (decimal): the second largest possible real would be 1 1111 1111 1000 000 = 0x1ff80 = 130,944 - the numbers are only accurate to about 4 decimal digits; the largest decimal real number would be 1.310 × 10^5, and the next 1.309 × 10^5 and so on. However, with proper IEEE, an exponent with all bits set is used to identify special numbers, which makes the largest possible 0111 1101 1111 1111 which is 1.1111 1111 11 × 10^1111 = 1111 1111 1110 0000 = 0xffe0 = 65504 accurate to ±16, ie the largest is about 6.55 × 10^4. * a nybble is half a byte which is directly representable as a single hexadecimal digit.


What is the binary equivalent of 33 in decimal?

3310 = 1000012