The number of binary operations that can be defined on a set with 4 elements is 4^(4*4) = 4^16 = 4.294.967.296
4
The number 23 is 10111 in binary. The digits in a binary number are exponents of 2 rather than 10, so that for a five digit number in binary, the digit places represent 16, 8, 4, 2, 1 instead of increasing values of 10. 10111 = 16+0+4+2+1 = 23
The binary number 1000 is the decimal (base 10) number 8. The digits in a binary number are exponents of 2 rather than 10, so that for a four-digit number in binary, the digit places represent 8, 4, 2, 1 1000 (binary) = 8 + (0x4) + (0x2) + (0x1) = 8
11100 = 8192 + 2048 + 512 + 256 + 64 + 16 + 8 + 4 So 1110010 = 10,101,101,011,100 in binary.
Binary 100 is 4 in decimal.
The number of binary operations that can be defined on a set with 4 elements is 4^(4*4) = 4^16 = 4.294.967.296
4
15
The number 23 is 10111 in binary. The digits in a binary number are exponents of 2 rather than 10, so that for a five digit number in binary, the digit places represent 16, 8, 4, 2, 1 instead of increasing values of 10. 10111 = 16+0+4+2+1 = 23
The binary number 1111 is 15. The digits in a binary number are exponents of 2 rather than 10, so that for a four digit number in binary, the digit places represent 8, 4, 2, 1 instead of increasing values of 10. 1111 = 8+4+2+1 = 15
151 = 128 + 16 + 4 + 2 + 1 so binary is 10010111
4
It is the binary number 1010100. A binary number represents exponential values of 2, in this case 7 digits for 64, 32, 16, 8, 4, 2, and 1 84 = 64 + (0x32) + 16 + (0x8) +4 + (0x2) + (0x1) = 1010100
The remainder of the division, by 4, is a number between 0 and 3. In the case of binary, this would maintain the last two bits of the original number.
The binary number 1000 is the decimal (base 10) number 8. The digits in a binary number are exponents of 2 rather than 10, so that for a four-digit number in binary, the digit places represent 8, 4, 2, 1 1000 (binary) = 8 + (0x4) + (0x2) + (0x1) = 8
The binary number is 11101110. A binary number represents exponential values of 2, in this case 8 digits for 128, 64, 32, 16, 8, 4, 2, and 1 238 = 128 + 64 + 32 + (0x16) + 8 + 4 + 2 + (0x1)