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What is the center of the circle given by the equation (x - 3)2 plus (y - 9)2 16?
Updated: 9/26/2023
Wiki User
∙ 7y agoBest Answer
If you mean: (x-3)^2 +(y-9)^2 = 16 then the center of the circle is at (3, 9)
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∙ 7y agoThis answer is:
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