By subtracting one term from the next the common difference can be found:
Using -8 and -13:
-13 - -8 = 13 + 8 = -5
→ Common difference is -5.
It is -5.
-8
34555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555345676543456
This is an arithmetic sequence with the first term t1 = 1, and the common difference d = 6. So we can use the formula of finding the nth term of an arithmetic sequence, tn = t1 + (n - 1)d, to find the required 30th term. tn = t1 + (n - 1)d t30 = 1 + (30 - 1)6 = 175
1, -3, -7
This is an Arithmetic Series/Sequence. In general the nth term, A(n) = a + (n - 1)d....where a is the 1st term and d is the common difference. In this question, the 1st term equals 1 and the common difference is 4. Then the nth term, A(n) = 1 + (n - 1) x 4 = 1 + 4n - 4 = 4n - 3.
This is an arithmetic sequence which starts at 14, a = 14, and with a common difference of -1, d = -1. We can use the nth term formula an = a + (n - 1)d to get an = 14 + (n - 1)(-1) = 14 - n + 1 = 15 - n.
What is the 14th term in the arithmetic sequence in which the first is 100 and the common difference is -4? a14= a + 13d = 100 + 13(-4) = 48
An excellent example of an arithmetic sequence would be: 1, 5, 9, 13, 17, in which the numbers are going up by four, thus having a common difference of four. This fulfills the requirements of an arithmetic sequence - it must have a common difference between all numbers.
-13
34555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555345676543456
Arithmetic
The nth term of an arithmetic sequence is given by. an = a + (n – 1)d. The number d is called the common difference because any two consecutive terms of an. arithmetic sequence differ by d, and it is found by subtracting any pair of terms an and. an+1.
Arithmetic- the number increases by 10 every term.
The common difference is 13 because 21-8=13, 34-21=13, and 34-47=13.
100 - 13(4) = 48 or 100 + 13(4) = 152. (It was not stated whether the difference given is [term - preceding term] or [term - succeeding term]. * * * * * The common difference is defined as [term - preceding term] so the first answer is the correct one: 100 - 13*4 = 48
arithmetic
It is: 9
This is an arithmetic sequence with the first term t1 = 1, and the common difference d = 6. So we can use the formula of finding the nth term of an arithmetic sequence, tn = t1 + (n - 1)d, to find the required 30th term. tn = t1 + (n - 1)d t30 = 1 + (30 - 1)6 = 175