0
-5 - 7i
Wiki User
∙ 12y ago
Add your answer:
Earn +20 pts
How do you determine the absolute value of a complex conjugate?
the absolute value of x + iy is equal to (x^2+y^2)^.5 and is the same for the conjugate, x-iy
The product of the complex numbers 4 3i 3 - 4i?
The easiest way to do this is treat i like a variable and multiply the binomials and combine like powers of i, then anywhere there is i², substitute it with (-1).So (4 + 3x)(3 - 4x) = {using FOIL} 4*3 - 4*4*x + 3*3*x - 3*4*x² = 12 -7x - 12x²So with x = i, you have 12 - 7i - 12*(i²) = 12 - 7i - -12 = 24 - 7iOne quick check to see if there is an error: The magnitude of the product of the two complex binomials will equal the product of the magnitude of each factor.Magnitude of a + bi = sqrt(a² + b²). The magnitudes of two numbers that are multiplied are: sqrt(4² + 3²) = 5, and sqrt(3² + (-4)²) = 5. The magnitude of the answer is sqrt(24² + (-7)²) = sqrt(576 + 49) = sqrt(625) = 25, which is 5 times 5.
Plot -5 plus 9i in a complex plane?
Start where the x and y axes cross. Go 5 units to the left on the x (horizontal axis) and then go 9 units up from there. Put a dot in that spot.
What is true about the complex number -5-5i?
That 5 is a factor.
Find the absolute value of the complex number z equals 3 plus 4i?
('|x|' = Absolute value of x) |3+4i| = √(32 + 42) = √(9+16) = √25 = 5 Thus |3+4i| = 5.
What is the complex conjugate of a plus bi?
The complex conjugate of a+bi is a-bi. This is written as z* where z is a complex number. ex. z = a+bi z* = a-bi r = 3+12i r* = 3-12i s = 5-6i s* = 5+6i t = -3+7i = 7i-3 t* = -3-7i = -(3+7i)
Write the complex number 2 - i divided by 5 plus i in the usual a plus bi form?
7
Complex conjugate of 5i?
0 + 5i Its complex conjugate is 0 - 5i
What is the usefulness of the conjugate and its effect on other complex numbers?
The conjugate of a complex number is the same number (but the imaginary part has opposite sign). e.g.: A=[5i - 2] --> A*=[-5i - 2] Graphically, as you change the sign, you also change the direction of that vector. The conjugate it's used to solve operations with complex numbers. When a complex number is multiplied by its conjugate, the product is a real number. e.g.: 5/(2-i) --> then you multiply and divide by the complex conjugate (2+i) and get the following: 5(2+i)/(2-i)(2+i)=(10+5i)/5=2+i
What is the conjugate of 5- square root 3?
2
How do you do the math problem (4-3i)(5 2i)?
To multiply complex numbers you can use the same FOIL rule that you use for multiplying binomials (First, Inside, Outside, Last).(4 - 3i)(5 + 2i) = (4)(5) +(4)(2i) - (3i)(5) - (3i)(2i) = 20 + 8i-15i - 6(i)^2= 20 -7i - 6(-1) = 20 + 6 -7i = 26 -7i.
What is the radix of x2-10x plus 31 equals 0 is x equals 5 and x equals 8?
No.The roots are the complex conjugate pair 5 ± 2.4495iwhere i is the imaginary square root of -1.
How do you determine the absolute value of a complex conjugate?
the absolute value of x + iy is equal to (x^2+y^2)^.5 and is the same for the conjugate, x-iy
Graphs of a complex number and its conjugate?
For example, the conjugate of 5 + 3i is 5 - 3i. The graph of the first number is three units above the real number line; the second one is three units below the real number line.
What is the absolute value of 7i?
The absolute value is sqrt(72 + 12) = sqrt(49 + 1) = sqrt(50) or 5*sqrt(2) = 7.071 approx.
What is a conjugate number of 2 plus square root of 5?
[ 2 minus square root of 5 ] is the only one.
What multiplies to 3 but adds to 2?
5
