4
4
Minus square root of 2, minus square root of 3, minus pi, minus e, etc. Or, to be a bit more fancy, 1 - pi, 2 - pi, 3 - pi, pi - 4, pi - 5, 2 - e, e - 3, square root of 2 minus 2, etc.
sqrt(18) - sqrt(8) = sqrt(2)
If the positive square root (for example, square root of 2) is irrational, then the corresponding negative square root (for example, minus square root of 2) is also irrational.
The square root of 4x^2 is solved by first doing the square root of 4. This is plus or minus two - because -2 x -2=4. The square root of x^2 is x. So the answers are 2x or -2x. If your question was (4x)^2, then the answer would be 4x.
(x^2+x-1/2)= x(x+1)-1/2 [x + (1 - square root of 3)/2][x + (1 + square root of 3)/2] = 0 Check it: x^2 + x/2 + (square root of 3)x)/2 + x/2 + 1/4 + (square root of 3)/4 - (square root of 3)x/2 - (square root of 3)/4 - 3/4 = 0 x^2 + x/2 + x/2 + [(square root of 3)x]/2 - [(square root of 3)x]/2 + (square root of 3)/4 - (square root of 3)/4 + 1/4 - 3/4 = 0 x^2 + x - 2/4 = 0 x^2 + x - 1/2 = 0 How to find this roots: Using the completing the square method: x^2 + x - 1/2 = 0 x^2 + x = 1/2 x^2 + x + 1/4 = 1/2 + 1/4 (x + 1/2)^2 = 3/4 x + 1/2 = (plus & minus)(square root of 3/4) x = -1/2 + (square root of 3)/2 x = - 1/2 - (square root of 3)/2
[ 2 minus square root of 5 ] is the only one.
2 square root 2
The square root of -4 is: 2 i
24
Yes. For example, the conjugate of (square root of 2 + square root of 3) is (square root of 2 - square root of 3).
Yes and x = 2+square root of 6 or x = 2-square root of 6
Minus square root of 2, minus square root of 3, minus pi, minus e, etc. Or, to be a bit more fancy, 1 - pi, 2 - pi, 3 - pi, pi - 4, pi - 5, 2 - e, e - 3, square root of 2 minus 2, etc.
The complex conjugate pair, -6 -8.7178i and -6 +8.7178i where i is the imaginary square root of -1.The complex conjugate pair -6 -8.7178i and -6 +8.7178i where i is the imaginary square root of -1.
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It is: (3*2)-(2*2) = 2
-184
sqrt(18) - sqrt(8) = sqrt(2)