Converse of the Perpendicular Bisector Theorem - if a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment.
Example: If DA = DB, then point D lies on the perpendicular bisector of line segment AB.
you :))
The converse of perpendicular bisector theorem states that if a point lies on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment.
The perpendicular bisector theorem states that if a point is on the perpendicular bisector of a line segment, then it is equidistant from the endpoints of that segment. Conversely, if a point is equidistant from the endpoints of a segment, it lies on the perpendicular bisector of that segment. This theorem is a fundamental concept in geometry, often used in constructions and proofs.
The Angle Bisector Theorem states that given triangle and angle bisector AD, where D is on side BC, then . Likewise, the converse is also true. Not sure if this is what you want?
An angle bisector bisects an angle. A perpendicular bisector bisects a side.
A circle cannot form a perpendicular bisector.
The converse of perpendicular bisector theorem states that if a point lies on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment.
Biconditional Statement for: Perpendicular Bisector Theorem: A point is equidistant if and only if the point is on the perpendicular bisector of a segment. Converse of the Perpendicular Bisector Theorem: A point is on the perpendicular bisector of the segment if and only if the point is equidistant from the endpoints of a segment.
converse of the perpendicular bisector theorem
If a point is on the perpendicular bisector of a segment, then it is equidistant, or the same distance, from the endpoints of the segment.
converse of the angle bisector theorem
The perpendicular bisector theorem states that if a point is on the perpendicular bisector of a line segment, then it is equidistant from the endpoints of that segment. Conversely, if a point is equidistant from the endpoints of a segment, it lies on the perpendicular bisector of that segment. This theorem is a fundamental concept in geometry, often used in constructions and proofs.
No, it does not.
If a point is on the bisector of an angle, then it is equidistant from the two sides of the angle-apex
The Angle Bisector Theorem states that given triangle and angle bisector AD, where D is on side BC, then . Likewise, the converse is also true. Not sure if this is what you want?
An angle bisector bisects an angle. A perpendicular bisector bisects a side.
A circle cannot form a perpendicular bisector.
on the perpendicular bisector