Q: What is the correct formula to calculate a fuse rating?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

The formula you are looking for is Watts = Amps x Volts. Amps = Watts/Volts. This comes to 4 amps load. Minimum size fuse would be 5 amps.

First of all you need to observe maximum current at various possible supply condition (i. e. 220VAC to 260VAC). Then check the inrush current for the equipment. When you start an high power device then it draws 4 times more current than usual. Your fuse should also take care of inrush current. For example: if maximum possible current is 500mA then your inrush current may go upto 2A. Thus if you put a fuse of 600mA then everytime you turn on the device, it may burn the fuse. So the suitable fuse for such condition is 2A

Disconnect the battery or pull the fuse to the horn then have an auto tech correct the problem.

Use this formula to convert degrees Celsius (C) to degrees Fahrenheit (F): (C x 1.8) + 32 = FUse this formula to convert degrees Fahrenheit (F) to degrees Celsius (C): (F - 32) / 1.8 = C

No such thing as a 5V fuse. There is a 5 Amp fuse. These are availableat an auto parts store.

Related questions

Watts divided by volts = amps

A fuse is given a various rating (strength). For instance, a home appliance (washing machine, etc) would usually have a fuse with a 13 amp rating. While a low powered lamp would only merit a 2 or 5 amp fuse rating. It is important to use a fuse of the correct rating in amps for each electrical appliance.

A: The VA rating is there 6v/a the power fuse to blow is 6watts. 050a fuse

A fuse rating is normally the 120% of the rated full load current. So, 4 amps times 120% is (4x120%) = 4.8amps

what is the correct fuse rating to provide short-circit protection for a100 HP 200V 3-0 wound-rotor motor

Using a fuse correctly rated for current but "overrated" for voltage does not present a problem. Current ratings are critical safety issues, and fuses should be replaced with those of the same current rating. But using a fuse with an identical current rating but a higher voltage rating is not a problem. The reason for that lies in what the voltage rating of a fuse is. Fuses are given a voltage rating to state a maximum voltage in a circuit that they are designed to protect. And the voltage rating has nothing to do with the "normal" operation of the fuse. The fuse carries current when it operates normally, but when something happens and excessive current flows, the fusible link heats up and opens. This is where the voltage rating comes into play. It is possible that a fuse can arc through when it fails. It is the voltage rating that stands in the way of this. As long as the voltage rating of a circuit is not beyond the voltage rating of the fuse, that fuse will fail safely when it fails. It is acceptable to use a fuse of an equal current rating but a higher voltage rating when replacing a fuse that has failed.

It is ok to use a fuse with a higher amperage rating and not ok to use a fuse with a smaller amperage rating why?

Fuses are rated in amps not watts. You just replace the fuse with one of the exact same amp rating as the one that blew. The fuse is protecting the wiring which you normally cannot change. For that reason you must use the correct rated fuse.

The fuse rating should be 5 amps

The current rating is 2A (2 amps).

Each fuse has its own rating. It will be marked on the fuse somewhere.