4in2
two square inches
3*sqrt(3)/2*r^2
The cross section of a cylinder is a circle. diameter = radius x 2 area_circle = π x radius2 ⇒ radius = √(area_circle ÷ π) ⇒ diameter = √(area_circle ÷ π) x 2 = √(706.86 sq in ÷ π) x 2 ≈ 30 in
If we denote the measure of the length side of the circumscribed square with a, then the vertexes of the inscribed square will point at the midpoint of the side, a, of the circumscribed square.The area of the circumscribed square is a^2The square measure of the length of the inscribed square, which is also the area of this square, will be equal to [(a/2)^2 + (a/2)^2]. Let's find it:[(a/2)^2 + (a/2)^2]= (a^2/4 + a^2/4)= 2(a^2)/4= a^2/2Thus their ratio is:a^2/(a^2/2)=[(a^2)(2)]/a^2 Simplify;= 2
The area of a square is the (perimeter/4)^2. The perimeter is 52, so 52/4=13. 13^2 is 169. The area of the square is 169 cm.^2.
two square inches
3.1416"Answer:3.1416 square inches.
Usually it means a piece of wood/lumber that has a cross-sectional area of 4 square inches, meaning that the cross section is a square of 2 inch side.
Volume = cross sectional area * lengthArea = 2* cross sectional area + perimeter of cross section * length
7.07 square feet
7.07 square feet
Measure the diameter = d cm. Then radius = d/2 cm and cross sectional area = pi*r2 cm2.Measure the diameter = d cm. Then radius = d/2 cm and cross sectional area = pi*r2 cm2.Measure the diameter = d cm. Then radius = d/2 cm and cross sectional area = pi*r2 cm2.Measure the diameter = d cm. Then radius = d/2 cm and cross sectional area = pi*r2 cm2.
To derive the cross sectional area of a two liter bottle do the following formula. Area = (radius * 2.54 cm/in)^2 * pi = X cm^2.
Divide volume by height will give you cross sectional area. The cross section of a cylinder is a circle. Area of a circle= π r2 divide your value of cross sectional area by π square root this value and multiply it by 2 that value is diameter.
3*sqrt(3)/2*r^2
1/2 ( a + b) x h
= area of a circle = pi*r^2 or length x width if the cross section is longitudinal (since the area will be rectangular)