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What is the cross sectional area of a tube with an outer diameter is 3.42 cm and an inner diameter of 2.4 cm?
Wiki User
∙ 7y ago
take the difference of areas of the outer and inner diameters
A = pi x (3.42 squared - 2.4 squared) divided by 4
pi = 3.14
A = 4.66 sq cm
3.77 cm
Wiki User
∙ 7y ago
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