density = mass/volume,
so the density of your metal is:
25/10 = 2.5g/cm3 (grams per cm cubed)
Density = Mass/Volume = 57.2g/11 cm3 = 5.2 gcm-3
10.5 g cm-3
Volume cannot be 29.4 cm since that is a measure of a length, not volume. Assuming that you meant 29.4 cm3, the density is mass/volume = 25.0 g / 29.4 cm3 = 0.850 grams per cubic centimetre (to 3 dp).
Density = mass/volume = 75g/1500 cm3 = 1/200 g/cm3 = 0.050 g/cm3That value is half of common balsa wood density (there are other woods that are less dense but your example is rater extreme)
Place the piece of metal in 50mL of water and subtract the 50mL from the new volume of water. The difference will be the volume of the metal in mL and cm3. Then find the density by dividing the mass by the volume of the metal. The water must completely cover the metal in order for the displacement method of determining the volume to work.
-- Get a pure piece of it. The size of the piece doesn't matter. -- Measure the mass of the piece. -- Measure the volume of the piece. -- The density of the substance is mass of the piece/volume of the piece.
2
That would vary greatly depending on the type and density of the metal, along with the dimensions of the particular piece. The weight of a piece of anything is the volume times the density.
Density = Mass/Volume = 57.2g/11 cm3 = 5.2 gcm-3
10.5 g cm-3
The density is the ratio of mass to volume. It doesn't matter what size the piece of metal, if it is the same metal it has the same density, 8.4.
Volume = mass/volume = 500g/10cm3 = 50g/cm3
Density= mass/volume 25/10 = 2.5 g/cm3
Density = Mass/Volume so Volume = Mass/Density. That is, Vol = 1.5 g/2.3 g/ml = 0.652 ml approx.
Density = Mass/Volume = 16/2.8 g/mL = 5.714 grams per mL (approx).
The volume of the piece of metal is measured by the difference in the volume of water in the graduated cylinder before and after the piece of metal is placed in the cylinder. This is stated to be 36 - 20 = 16 mL. Density is defined to be mass per unit volume. Therefore, for this piece of metal the density is 163/16 = 10 g/mL. (Only two significant digits are justified, because the is the number of significant digits in the limiting datum 16.)
If the water is at standard temperature and pressure (25 degrees Celsius and one atmosphere), the water has density of 1 kilogram per liter. When submerged, the metal displaces its own volume of water. Therefore, the volume of the metal is 1 liter, and the density of the metal is 6 kg/liter.