answersLogoWhite

0


Best Answer

271

User Avatar

Otis Steuber

Lvl 10
3y ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

10y ago

Density = mass/volume. There is no information about the volume and so no answer is possible.

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is the density of a 270g cube if twenty-seven 1g marbles are added to the inside of the cube?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is the result when marbles are added to a beaker of salt?

The marbles will pulverize the salt crystals so much that the salt looks like a powder but the salt has actually been reduced to very small crystals.


Why did an egg float when the salt is added to the water?

When salt is added to water, the density of water increases. Therefore the density of egg becomes less than the density of water therefore it begins to float in water.


Why does water's density decrease after potassium chloride salt is added?

The water density doesn't decrease.


What happens to the density when heat is added?

The density of air when it is heated decreases


How can an objects density change?

It can if more of the substance is added to it.


Why does the density of water increase when salt is added to it?

Density = Mass/Volume As salt(mass) increases and the volume remains the same, density also increases.


How does the amount of salt added to the water affect buoyancy?

density


There are red and blue marbles in a jar one-third of the marbles are red if another marble is added to the jar then 3 8 of the marbles will be red how many marbles are blue?

Depends on what the question is actually saying:If the "3 8" is 38 (thirty eight):Let R = number of red marbles to begin with.Let B = number of blue marblesGiven two facts:R = (1/3)(R+B)R+1 = 38. (This assumes it's a red marble added)2nd equation gives R = 371st equation gives B = 2R = 2*37 = 74 blueIf the "3 8" is 3 over 8 (3/8 or three eighths):If a non-red marble is added, the problem is unsolvable as 3/8 is greater than 1/3, but with more marbles and the same number of red marbles, the fraction of red marbles will be less than 1/3. Thus it is assumed that a red marble is added:Let M be the number of marbles in the jar, and R be the number of red ones, then:1/3 M = R -- one third are red3/8 (M + 1) = R + 1 -- when an extra red marble is added, 3/8 of the marbles are now red marblesSubstituting R from the first equation into the second equation gives and solving gives:3/8 (M + 1) = 1/3 M + 1→ 9/8 (M + 1) = M + 3→ 9(M + 1) = 8M + 24→ 9M + 9 = 8M + 24→ 9M = 8M + 15→ M = 151/3 are red → 2/3 are blue→ 2/3 x 15 = 10 are blue................................................................................................................................Another Answer:1/3+1/24 = 3/8 It doesn't how many red marbles are added because now there are 24 but before there were 23 which is 1/3 of 69 of which 2/3 are 46 blue marbles.


Does a change in the mass affect the density of the object?

Adding mass may increase or decrease the density if the substance added is different. Merely changing the mass will not affect the density.


What happens to the density of water when shaved ice is added to water to make it slushy?

-- The average density of the entire contents of the container decreases,because the density of the shaved ice is less than the density of the waterto which it was added.-- The density of the water alone increases steadily as it cools to 4°C (39°F),then decreases as the water cools further to a lower temperature.


What happens to the density of water when shaved ice is added to water to make it a slushy?

-- The average density of the entire contents of the container decreases,because the density of the shaved ice is less than the density of the waterto which it was added.-- The density of the water alone increases steadily as it cools to 4°C (39°F),then decreases as the water cools further to a lower temperature.


Why does adding salt to water inccrease its density?

because you added sodium, duuuh