38.75g. Or, in keeping with the correct number of significant figures, 38.8g.
Since the formula for density is D(ensity) = M(ass) / V(olume, the corresponding formula for mass must be M(ass)= D(ensity) x V(olume)
What is the mass of a solution that has a density of 0.775g/ml and a volume of 50.0ml?
This is a simple calculation. .775 g/ml x 50 ml = 38.75 g.
D=m/v
D=50/100
D=0.5 g/cm cubed
Density = Mass/Volume = 7.5g/5.0mL = 1.5 g per mL
density = mass/volume
To solve for mass:
mass = density x volume = 2.10g/mL x 50.0mL = 105g
Its density is 0.5 g/mL
0.775 x 50 = 38.75grams
5 g/mL
0.0155 g/ml
Yes, this is exactly it. If you don't have a litre, it is still a certain molarity solution, provided you know the amount of moles. For example. 2 moles in 500ml. If there are 2 moles in every 500ml, there will be 4 moles in every 1000ml, i.e. 4 molar.
500 ml
Molarity (M) is defined as moles of solute/liters of solution. Assuming the final volume is 500 ml (0.5 liters), then M = 1.2 moles/0.5 liters = 2.4 M
Simple equality. (100ml)(7%) = (500ml)(X%) = 1.4%
50 micrograms per millilitre is the same as 50*500 i.e. 25,000ug per 500ml. 25000ug is 25mg. In every ml, there are 50mg, so you only need half of a millilitre.
In order to find out how many grams is in 500ml, one must have a measurement of density available. If density is not known, it can be found by finding the volume of the substance in ml, finding mass in grams, and dividing mass by volume. From there, multiply the result by 500ml to find the amount of grams in 500ml of the substance.
molarity equals moles of solute /volume of solution in litres . moles of NaOH equals 5g/40g = 0.125 and volume of solution will be volume of water + volume of NaOH = 0.5 litre+0.002 l which is nearly 0.5 litre . (volume of NaOH is calculated by its density) so molarity = 0.125mol/0.5litre = 0.25 M
if you assume 1g/ml density, 500ml
A 3 Molar solution has 3 moles of reagent per liter. 500mL of that solution has 1.5 moles of reagent. So to create a 2 moles per liter solution with 1.5 M or reagent, you will need a volume of 750 mL. So you will need to add 250 mL of water.
Yes, this is exactly it. If you don't have a litre, it is still a certain molarity solution, provided you know the amount of moles. For example. 2 moles in 500ml. If there are 2 moles in every 500ml, there will be 4 moles in every 1000ml, i.e. 4 molar.
60ml.
500 ml
to make 500ml of 1x TAE solution we have to take 5ml of 100x TAE solution. mix it in 495 ml of deionized water.
You need to bring this to a litre. If there is 1 mole in 500ml (using ratio), there will be 2 moles in a litre. So your molarity is 2.
700 g
Tidal volume is the volume of air that moves in and goes out in asingle stroke, and is abut 500ml.
Take 5 grams of calcium chloride and dissolve it in 100ml of solution to get a 5% solution of calcium chloride. The standard way to make a weight-volume solution is to take grams of the dry substance in 100ml of volume.