Write it as (1/3)x and take the derivative. You get (1/3)x0 = 1/3 * 1 = 1/3 ■
-3 divided by x2
(1/2(x^-1/2))/x
Well if you have 5/X then you can rewrite this like 5x-1. And the derivative to that is -5x-2 and that can be rewrote to: -(5/x2).
x/3
The anti-derivative of X2 plus X is the same as the anti-derivative of X2 plus the anti-derivative of X. The anti derivative of X2 is X3/3 plus an integration constant C1 The anti derivative of X is X2/2 plus an integration constant C2 So the anti-derivative of X2+X is (X3/3)+(X2/2)+C1+C2 The constants can be combined and the fraction can combined by using a common denominator leaving (2X3/6)+(3X2/6)+C X2/6 can be factored out leaving (X2/6)(2X+3)+C Hope that helps
(X^3-27) divided by (x-3)
Following the correct order of operations: derivative of x^2 + 6/2 = derivative of x^2 +3, which equals 2x
the derivative of 3x is 3 the derivative of x cubed is 3 times x squared
d/dx of 6*x^(-1/3) = (-6/3)*x^(-4/3) = -2*x^(-4/3), by power rule
1 divided by x to the third power equals x to the negative third. The derivative of x to the negative third is minus three x to the negative fourth.
Negative the derivative of f(x), divided by f(x) squared. -f'(x) / f²(x)
-4/x2
x4/12 since derivative of x4/12 is 4x3/12 or x3/3
m
10/x3 = 10 x-3d/dx(10x-3) = -30 x-4 = -30/x4
Use the rule for multiplication with a constant - and look up the derivative of "cos x" in a basic table of derivatives. The answer is 3 times the derivative of cos x.
if y=7/(x^3)-4/xthenby the quotient ruley'=(((0)(x^3)-(7(3x^2))/((x^3)^2))-(((0x)-(4))/(x^2))
You can estimate the derivative by looking at adjacent rows of the table, and calculate (difference of y-coordinates) divided by (difference of x-coordinates).