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Assuming you want dx/dt and that the equation is
x = cot(2) / t
(i.e. cot(2) is a constant)
we can use the power rule. First, we rewrite it:
cot(2)/t = cot(2) * t-1
thus, by the power rule:
dx/dt = (-1) cot(2) * t-1 -1 = - cot(2) * t-2= = -cot(2)/t2
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How do you compute the derivative of the given function g of t equals 2 divided by t and t equals 1 divided by 2?
g(t) = 2/tThe function is the same as writing g(t) = 2 t-1,and that's not too difficult to differentiate:g'(t) = -2 t-2g'(1/2) = -2 (1/2)-2 = -2 (4) = -8
If v equals m times t divided by a what does m equal?
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How do you compute the derivative of the given function g of t equals 2 divided by t and t equals 1 divided by 2?
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If v equals m times t divided by a what does m equal?
divided by what? m will be equals to t divided by v
A equals vf-vi divided by t?
(vf-vi)/ t is ?
How do you get the second derivative of g of x equals xcscx where x equals theta?
T=theta so that it will not look so messy. g(T)=TcscT To find the first derivative, you must use the product rule. Product rule is derivative of the first times the second, plus the first times the derivative of the second, which will give you: g'(T)=0xcscT + Tx-cscTcotT, which simplifies: g'(T)= -cscTxcotT Now, take the derivative of that to get the second derivatice. In order to do that, you have to do the product rule again. g"(T)=(cscTcotT)cotT + -cscT(-csc^2T) {that's csc squared} which simplifies: g"(T)= cscTcot^2(T) + csc^3 (T)
Is distance divided by time equals equals to velocity?
Yes, V (velocity) = d (distance) divided by t (time).
What are two different word phrases for the expression t divided by 30?
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0.8333
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9 + t/12 = -3 t/12 = -12 t = -144
