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What is the derivative of x raised to the 1 plus square root of 2?
Wiki User
∙ 14y ago
If you mean:
f(x) = x1 + root(2)
The derivative of x1, or x, is simply 1. The derivative of the square root of 2, just like the derivative of any constant, is zero. Therefore, the derivative of the entire function is one.
If you mean:
f(x) = x1 + root(2)
you shuld use the power rule (the exponent, multiplied by x to the power (exponent minus 1)):
(1 + root(2)) xroot(2)
If you mean:
f(x) = x1 + root(2)
The derivative of x1, or x, is simply 1. The derivative of the square root of 2, just like the derivative of any constant, is zero. Therefore, the derivative of the entire function is one.
If you mean:
f(x) = x1 + root(2)
you shuld use the power rule (the exponent, multiplied by x to the power (exponent minus 1)):
(1 + root(2)) xroot(2)
If you mean:
f(x) = x1 + root(2)
The derivative of x1, or x, is simply 1. The derivative of the square root of 2, just like the derivative of any constant, is zero. Therefore, the derivative of the entire function is one.
If you mean:
f(x) = x1 + root(2)
you shuld use the power rule (the exponent, multiplied by x to the power (exponent minus 1)):
(1 + root(2)) xroot(2)
If you mean:
f(x) = x1 + root(2)
The derivative of x1, or x, is simply 1. The derivative of the square root of 2, just like the derivative of any constant, is zero. Therefore, the derivative of the entire function is one.
If you mean:
f(x) = x1 + root(2)
you shuld use the power rule (the exponent, multiplied by x to the power (exponent minus 1)):
(1 + root(2)) xroot(2)
Wiki User
∙ 14y ago
Wiki User
∙ 14y agoIf you mean:
f(x) = x1 + root(2)
The derivative of x1, or x, is simply 1. The derivative of the square root of 2, just like the derivative of any constant, is zero. Therefore, the derivative of the entire function is one.
If you mean:
f(x) = x1 + root(2)
you shuld use the power rule (the exponent, multiplied by x to the power (exponent minus 1)):
(1 + root(2)) xroot(2)
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How do you get the derivative of a square root?
The square root of x = x to the power of a half
What is the derivative of the square root of 2?
The derivative of sqrt(2) is zero.
What is the derivative of square root of x-5?
Use the formula for the derivative of a power. The square root of (x-5) is the same as (x-5)1/2.
Square root of 27 plus the square root of 75 equal?
square root of 27 plus the square root of 75
How do you differentiate cosine square root of x?
The derivative of cos x is -sin x, the derivative of square root of x is 1/(2 root(x)). Applying the chain rule, the derivative of cos root(x) is -sin x times 1/(2 root(x)), or - sin x / (2 root x).
How do you get the derivative of a square root?
The square root of x = x to the power of a half
What is the derivative of square root of 2?
the derivative is 0. the derivative of a constant is always 0.
What is the derivative of the square root of 2?
The derivative of sqrt(2) is zero.
What is the derivative of square root of x-5?
Use the formula for the derivative of a power. The square root of (x-5) is the same as (x-5)1/2.
What does the square root of 27 plus the square root of 5?
The square root of 27 plus the square root of 5 = 7.4322204
Square root of 27 plus the square root of 75 equal?
square root of 27 plus the square root of 75
How do you differentiate cosine square root of x?
The derivative of cos x is -sin x, the derivative of square root of x is 1/(2 root(x)). Applying the chain rule, the derivative of cos root(x) is -sin x times 1/(2 root(x)), or - sin x / (2 root x).
What is the square root of 96 raised to the 4th power?
The square root of 96 raised to the 4th power is 9,216.
What is the second derivative of the square root of x to the power of 3?
3/(4*square root(x)) ....Mukesh
What is the square root of 4 raised to the fifth power?
square root(4 raised to the fifth) = 32
What is the square root of 2 raised to the fifth power?
The square root of 2 raised to the fifth power equals 5.65685424949
What is the derivative of y equals square root of 8x plus square root of 4x?
y=(8x).5 + (4x).5 = (2+2sqrt(2))x.5 y'=(1 + sqrt(2))/sqrt(x)
