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y=-3x*sinx-1.5x2+5x, when x=π

y'=d/dx(-3x*sinx)-d/dx(1.5x2)+d/dx(5x)

y'=(-3x*d/dx(sinx)+sinx*d/dx(-3x))-d/dx(1.5x2)+d/dx(5x)

y'=(-3x*cosx+sinx(-3))-d/dx(1.5x2)+d/dx(5x)

y'=(-3x*cosx-3sinx)-3x+5

y'=-3x*cosx-3sinx-3x+5 is the derivative at any point of that equation, now you only have to plug in π for x

y'(π)=-3π*cosπ-3sinπ-3π+5

y'(π)=-3π*(-1)-3(0)-3π+5

y'(π)=3π-3π+5

y'(π)=5

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Q: What is the derivative of y equals -3xsinx - 1.5x to the 2 plus 5x when x equals pi?
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