10' x 16' is not a square but a rectangle and the diagonal is
square root of (10^2 + 16^2) =
square root of (100 + 256) =
square root of 356 which is 18.867 feet
18ft 10 and3/8
The side lengths of a square with a diagonal of 16 is: 11.31.
Around 17.8. I did this with cossin, but check the answer with a calculator
Sqrt (256 + 256) = sqrt 64 x sqrt 4 x sqrt 2 = 16 root 2 = just over 22' 7½".
Its perimeter is 4+4+4+4 = 16 units of measurement
Use the Law of Pythagoras - in this case, the answer is the square root of (162 + 92).
There is no such square with the given dimensions but if you mean the diagonal of a rectangle then by using Pythagoras' theorem it works out as 8 times the square root of 13
The side lengths of a square with a diagonal of 16 is: 11.31.
The diagonal is 20.
diagonal = sqrt(4^2 + 4^2) = sqrt(16 + 16) = sqrt(32) = 5.6568
Using Pythagoras' theorem the diagonal is 16 times the square root of 2
17.8885'
The diagonal is 20.
The length of one side of a square with a 16-centimeter diagonal is: 11.31 cm
That would be 34 feet.
16 cm squared.
It is 16*sqrt(2) feet.
16*sqrt(2) = 22.627 (to 3 dp).