The diagonal is 20.
20
20
20
17'
The diagonal is 20.
17.8885'
20 ft
The diagonal of a rectangle is measured by using Pythagores theorem if you have the length and breadth of the rectangle. Say the length is 4cm and breadth is 3cm then the diagonal(hypotenuse) would be 42 + 32 =16 + 9= 25 = 52. Hence the hypotenuse or the diagonal is 5cm. Is that fine? Have a good day.
There is no such square with the given dimensions but if you mean the diagonal of a rectangle then by using Pythagoras' theorem it works out as 8 times the square root of 13
The diagonal is 20.
17.8885'
That would be 34 feet.
Around 17.8. I did this with cossin, but check the answer with a calculator
Width is 16.
20 ft
Using Pythagoras' theorem the length of the diagonal is 20 feet
The diagonal of a rectangle is measured by using Pythagores theorem if you have the length and breadth of the rectangle. Say the length is 4cm and breadth is 3cm then the diagonal(hypotenuse) would be 42 + 32 =16 + 9= 25 = 52. Hence the hypotenuse or the diagonal is 5cm. Is that fine? Have a good day.
There is no such square with the given dimensions but if you mean the diagonal of a rectangle then by using Pythagoras' theorem it works out as 8 times the square root of 13
26.4 inches for the diagonal.
10' x 16' is not a square but a rectangle and the diagonal is square root of (10^2 + 16^2) = square root of (100 + 256) = square root of 356 which is 18.867 feet
If the length of a rectangle is 12 and the width of the rectangle is 16, by the Pythagorean theorem we know that one diagonal is 20 units long. You can draw two diagonals within a rectangle, so the length of both diagonals together is 20+20 = 40 units.