There is no such square with the given dimensions but if you mean the diagonal of a rectangle then by using Pythagoras' theorem it works out as 8 times the square root of 13
It is 16*sqrt(2) feet.
The diagonal is 20.
diagonal = sqrt(4^2 + 4^2) = sqrt(16 + 16) = sqrt(32) = 5.6568
17.8885'
Using Pythagoras' theorem the diagonal is 16 times the square root of 13 or about 57.689 feet rounded to three decimal places
10' x 16' is not a square but a rectangle and the diagonal is square root of (10^2 + 16^2) = square root of (100 + 256) = square root of 356 which is 18.867 feet
That would be 34 feet.
It is 16*sqrt(2) feet.
Sqrt (256 + 256) = sqrt 64 x sqrt 4 x sqrt 2 = 16 root 2 = just over 22' 7½".
diagonal^2 = 16^2 + 24^2 = 256 + 576 = 832 Therefore diagonal is square root of 832 = 28.8444 feet
The side lengths of a square with a diagonal of 16 is: 11.31.
The diagonal is 20.
diagonal = sqrt(4^2 + 4^2) = sqrt(16 + 16) = sqrt(32) = 5.6568
5.7 ft
You need another measurement to make it cubic.
Using Pythagoras' theorem the diagonal is 16 times the square root of 2
Just do the sum 16 times 8 times 8 and you will have your answer in square feet.