The diagonal measurement of an 8 ft square is: 11.31 feet.
I assume that you refer to a 12 ft x 12 ft 8 in square. The length of the diagonal is determined easily suing Pythororas's therem: Diagonal = sqrt[122 + (128/12)2] feet = sqrt(304.4... ) ft = 17.448 ft approx.
The diagonal of a rectangle 8 feet by 12 feet is √208 feet, or about 14 feet 5.06 inches.
the square root of 128 or 8 times the square root of 2.
The diagonal dimension is 11.31 feet.
8*sqrt(2) The diagonal of the square would be the hypotenuse of the right triangle formed by two of the sides of the square.
Don't tell me you are in class!
I assume that you refer to a 12 ft x 12 ft 8 in square. The length of the diagonal is determined easily suing Pythororas's therem: Diagonal = sqrt[122 + (128/12)2] feet = sqrt(304.4... ) ft = 17.448 ft approx.
The diagonal of a rectangle 8 feet by 12 feet is √208 feet, or about 14 feet 5.06 inches.
The square has a diagonal measurement of: 1.13 km
Around 17.8. I did this with cossin, but check the answer with a calculator
the square root of 128 or 8 times the square root of 2.
The diagonal of an 8 ft by 10 ft square, by Pythagoras, would be sqrt(82 + 102) = sqrt(64+100) = sqrt(164) = 12.806 ft (to 5 sig figs)
If you mean a rectangle then its diagonal using Pythagoras; theorem is 2 times the square root of 41 or about 12.806 feet rounded to 3 decimal places.
There is no such square with the given dimensions but if you mean the diagonal of a rectangle then by using Pythagoras' theorem it works out as 8 times the square root of 13
10' x 16' is not a square but a rectangle and the diagonal is square root of (10^2 + 16^2) = square root of (100 + 256) = square root of 356 which is 18.867 feet
17.8885'
The diagonal dimension is 11.31 feet.