2.8284 feet
The diagonal of a 30' x 30' square is: 42.43 feet.
The perimeter = 12 feetthen the square diagonal = 12/4 = 3 feet The diagonal2 = 3x3 + 3x3= 18 feetThe diagonal = square root of 18 = 3x 21/2 feet = 3 x 1.4142 = 4.2426 feet
The diagonal of a 36 x 36 foot square is 50.91 feet.
There is no such square with the given dimensions but if you mean the diagonal of a rectangle then by using Pythagoras' theorem it works out as 8 times the square root of 13
About 8.5 feet.
The diagonal of a 30' x 30' square is: 42.43 feet.
The perimeter = 12 feetthen the square diagonal = 12/4 = 3 feet The diagonal2 = 3x3 + 3x3= 18 feetThe diagonal = square root of 18 = 3x 21/2 feet = 3 x 1.4142 = 4.2426 feet
The diagonal of a 46' x 46' square is 65.05 feet.
10' x 16' is not a square but a rectangle and the diagonal is square root of (10^2 + 16^2) = square root of (100 + 256) = square root of 356 which is 18.867 feet
About 28.28 feet.
Area of Rhombus = length of first diagonal x length of second diagonal / 2 / means divided by So for your problem: Area of Rhombus = 10 feet x 14 feet / 2 = 70 square feet
The diagonal of a 36 x 36 foot square is 50.91 feet.
Using Pythagoras: 10 times square root of 2 feet
Use Pythagoras' theorem: 33.9411255 or about 34 feet
The diagonal of a square = the length of one side x the square root of 2 (approx 1.414)
The radius of a square is the radius of the circumcircle, ie the distance from the centre of the square to any vertex, which is half the length of the diagonal of the square. Using Pythagoras: diagonal^2 = side^2 + side^2 → diagonal = √(2 x side^2) area = side^2 → diagonal = √(2 x area) radius = 1/2 x diagonal = 1/2 x √(2 x area) → radius = 1/2 x √(2 x 72 sq in) = 1/2 x √(144 sq in) = 1/2 x 12 in = 6 in.
There is no such square with the given dimensions but if you mean the diagonal of a rectangle then by using Pythagoras' theorem it works out as 8 times the square root of 13