There is no difference, only your outcome. The formula for both is x+2
30 + 31 + 32 = 93 ( I forgot how to find this algebraically )
Algebraically, X = integer. X + (X + 1) = 89 2X + 1 = 89 2X = 88 X = 44 ------------so X + 1 which is 44 + 1 = 45 ( 44, 45) --------------are your consecutive integers
I assume you mean what are the two consecutive integers. Algebraically; X = integers.X + (X + 1) = 2752X + 1 = 2752X = 274X = 137============solution setorSince the consecutive integers differ by 1, then the first number is 274/2 = 137, so the second one is 1 more, 138.
56.25% is not an integer and so cannot be expressed as a sum, difference, product or quotient of consecutive integers.
Algebraically, with X = integers.X + (X + 1) + (X + 2) = 1923X + 3 = 1923X = 189X = 63============solution set
The first two consecutive prime numbers that have a difference of 20 are the numbers 887 and 907.
Algebraically. X = integers. X + (X + 1) = - 379 2X + 1 = - 379 2X = - 380 X = - 190 X + 1 = - 189 - 190 +(- 189) = - 379 ==============solution set of integers
Algebraically, X = integers. X + (X + 1) = 237 gather all terms on the left 2X + 1 = 237 subtract 1 from each side 2X = 236 divide both sides integers by 2 X = 118 --------------so, X + 1 = 119 ----------------so, The two consecutive integers that = 237 are 118 and 119 -------------------
All consecutive integers have a difference of one.
Algebraically. X = integers.X + (X + 1) = 592X + 1 = 592X = 58X = 29X + 1 = 30(29, 30)=======
-40
"Consecutive" integers are integers that have no other integer between them.