There are two parts to the rule:
If the last but one digit is even, the last digit must be 0, 4 or 8
If the last but one digit is odd, then the last digit must be 2 or 6.
Find the sum of the first, third, fifth, etc digits.
Find the sum of the second, fourth, sixth, etc digits.
The difference between these two sums must be a multiple of 11 ie 0, 11, 22, 33 etc.
Part 1 ensures divisibility by 4
Part 2 ensures divisibility by 11
Together, they ensure divisibility by 44.
There is no easy rule for divisibility by 34.
The divisibility rules of 4 and 9 are combined to make the divisibility rule of 36.
By tautology. If it did not work, it would not be a divisibility rule!
why does the divisibility rule work for 4
there is a divisibility for 24 the rule is you can divide 24 as 6 and 4 i think
What is the divisblity rule by 8
the divisibility rule for 2 is: The number is even;the last digit ends with a 2,4,6,8,10, etc.The divisibility rule fir 3 is: The sum of the number is divisible by 3The divisibility rule for 4 is: The last two digits are divisible by 4The divisibility rule for 5 is: The number ends with a 5 or 0The divisibility rule for 6 is: The sum CAN be divisible by 2 and or 3The divisibility rule for 9 is: The sum of the number is divisible by 9The divisibility rule for 10 is : The number ends with a 0
There is no rule for 7 :P
Able to Be Divided
The divisibility rule for 2 works because the base of our number system, 10, is divisible by 2.
the number is even.
It has to end 00.
it is divisible by5
It is 86
The rule for 1 and the rule for 3.
Judging by some of the questions asked on this site, the first rule is that divisibility is a concept that applies only to whole numbers.
2 squared 1 = 4 so the divisibility rule is that it is divisible by 1, 2 and 4.
By using the divisibility rule for 3, we find that 117 is divisible by 3. That makes it composite.
it is divisible by 3 and 9
3 - 31
Division by zero is undefined.
It is 3 6 9