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Whatever you choose. The function, itself, imposes no restrictions on the domain and therefore it is up to the person using it to define the domain. Having defined the domain, the codomain, or range, is determined for you.
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What are the X-intercept of the graph of the following Equation y equals x2 plus 6x-7?
x-intercept happens when y=0 0=x2+6x-7 0=(x - 1)(x + 7) x-intercepts are x=1 and -7
What is the factored form of x2 6x 8?
If you mean: x2+6x+8 then it is (x+4)(x+2) when factored
What is the factor of this trinomial x2-6x-27?
x2-6x-27 = (x+3)(x-9) when factored
X2 - 6x equals -8?
This is a quadratic equation question in finding the possible values of x x2 - 6x = - 8 x2 - 6x + 8 = 0 Factorise the expression in the equation: (x-2)(x-4) = 0 Therefore: x = 2 or x = 4
Find the value or values of x in the quadratic equation x2 equals 6x-9?
In the equation x2 = 6x - 9, all terms must be moved to one side of the equals sign, giving x2 - 6x + 9 = 0. This becomes factorable to (x -3)(x-3).
How do you find the vertex and graph?
y = - x2 +6x - 5.5
Factor 6 x2 - 11x?
x(6x - 11)
How do you graph y equals x2 plus 6x plus 7?
y = x2 + 6x + 7a = 1, b = 6, c = 7Since a is positive, the graph opens upward. You can find the vertex coordinates (-b/2a, f(-b/2a)) = (-3, f(-3)) = (-3, -2), so the equation of the axis of symmetry is x = -b/2a = -3, plot the y-intercept point (0, 7), plot the point (-b/a, 7) = (-6, 7), and draw the graph that passes through these points.Or complete the square.y = x2 + 6x + 7y = x2 + 6x + 9 - 9 + 7y = (x2 + 6x + 9) - 2y = (x + 3)2 - 2So start with the graph of y = x2 whose vertex is at the origin. Move it 3 units to the left, and 2 units do
What is the factor of x2-5x-66?
x2-5x-66 x2-11x+6x-66 x(x-11)+6(x-11) (x+6)(x-11)
What is the range of y equals x2 plus 6x plus 11?
y ≥ 11
How do you factor x2 6x-2?
x2 + 6x - 2 can not be factored
How to Graphs Y equals x2 plus 6x plus 7?
y = x2 + 6x + 7a = 1, b = 6, c = 7Since a is positive, the graph opens upward. You can find the vertex coordinates (-b/2a, f(-b/2a)) = (-3, f(-3)) = (-3, -2), draw the axis of symmetry, x = -b/2a = -3, plot the y-intercept point (0, 7), plot the point (-b/a, 7) = (-6, 7), and draw the graph that passes through these points.Or complete the square.y = x2 + 6x + 7y = x2 + 6x + 9 - 9 + 7y = (x2 + 6x + 9) - 2y = (x + 3)2 - 2So start with the graph of y = x2 whose vertex is at the origin. Move it 3 units to the left, and 2 units down.
How do you solve x2 6x 27?
please help on this x2+6x+27=
How do you Factorise this x2 plus 6x?
x2 + 6x = x*(x + 6)
If x is a positive integer solve x2 6x 16?
Um.......is it x2+6x or x2-6x. I think your missing some things here champ
Factorise x2 plus 6x-55 equals?
(x-5)(x+11)
X2 - 6x - 16?
x2 - 6x - 16 = (x - 8)(x + 2)
